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2 years ago

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Niagara Falls is a set of very large waterfalls located on the border between New York and Ontario, Canada. Over 200,000 cubic f

eet of fast-moving water falls approximately 180 feet every second. Water at the top of the Falls possesses
kinetic energy and gravitational potential energy.
only gravitational potential energy.
only kinetic energy.
neither gravitational potential energy nor kinetic energy.

2 answers:

Minchanka [31]2 years ago

7 0

The first choice is correct. It has both.

-- It has kinetic energy because it's "fast-moving" water.

-- It has gravitational potential energy because it's hundreds of feet
above the riverbed that it's getting ready to fall down to, as soon as
it goes over the edge.

vladimir1956 [14]2 years ago

3 0

Yep its A-kinetic energy and gravitational potential energy

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Answer:

A. $W=600\ J$

B. $Q=2112\ J$

C. $\Delta U=1512\ J$

D. $W=0\ J$

Explanation:

Given:

no. of moles of oxygen in the cylinder, $n=0.2$

initial pressure in the cylinder, $P_i=2\times 10^5\ Pa$

initial temperature of the gas in the cylinder, $T_i=360\ K$

<em>According to the question the final volume becomes twice of the initial volume.</em>

<u>Using ideal gas law:</u>

$P.V=n.R.T$

$2\times 10^5\times V_i=0.2\times 8.314\times 360$

$V_i=0.003\ m^3$

A.

<u>Work done by the gas during the initial isobaric expansion:</u>

$W=P.dV$

$W=P_i\times (V_f-V_i)$

$W=2\times 10^5\times (0.006-0.003)$

$W=600\ J$

C.

<u>we have the specific heat capacity of oxygen at constant pressure as:</u>

$c_v=21\ J.mol^{-1}.K^{-1}$

Now we apply Charles Law:

$\frac{V_i}{T_i} =\frac{V_f}{T_f}$

$\frac{0.003}{360} =\frac{0.006}{T_f}$

$T_f=720\ K$

<u>Now change in internal energy:</u>

$\Delta U=n.c_p.(T_f-T_i)$

$\Delta U=0.2\times 21\times (720-360)$

$\Delta U=1512\ J$

B.

<u>Now heat added to the system:</u>

$Q=W+\Delta U$

$Q=600+1512$

$Q=2112\ J$

D.

Since during final cooling the process is isochoric (i.e. the volume does not changes). So,

$W=0\ J$

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