Answer:
Explanation:
Given
Each student exert a force of
Let mass of car be m
there are 18 students who lifts the car
Total force by 18 students
therefore weight of car
mass of car
(b)
The spring constant for the spring in above Table is 20 N/m.
1 answer:
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Answer:
V = 90.51 m/s
Explanation:
From the given information:
Initial speed (u) = 0
Distance (S) = 391 m
Acceleration (a) = 18.9 m/s²
Using the relation for the equation of motion:
v² - u² = 2as
v² - 0² = 2as
v² = 2as
v = 121.57 m/s
After the parachute opens:
The initial velocity = 121.57 m/ss
Distance S' = 332 m
Acceleration = -9.92 m/s²
How fast is the racer can be determined by using the relation:
V = 90.51 m/s