3 years ago

I need help with this

Mathematics

2 answers:

Maksim231197 [3]3 years ago

8 0

Answer: 4.75

Step-by-step explanation:

klasskru [66]3 years ago

6 0

12/16 divided by 2 = 3/8

You might be interested in

Calculate 6+9i/-1+4i

lisabon 2012 [21]

Multiply the numerator and denominator by the conjugate of the denominator:

$\dfrac{6+9i}{-1+4i} \times \dfrac{-1-4i}{-1-4i} = \dfrac{(6+9i)(-1-4i)}{(-1)^2-(4i)^2}$

Simplify:

$\dfrac{(6+9i)(-1-4i)}{(-1)^2-(4i)^2} = \dfrac{-6-9i-24i-36i^2}{1-16i^2} = \dfrac{-6-33i-36i^2}{1-16i^2} = \dfrac{-6-33i+36}{1+16} = \boxed{\dfrac{30-33i}{17}}$

8 0

2 years ago

How do you know that dividing by 1/6 is the same as multiplying by 6?

Natasha2012 [34]

Answer:6

Step-by-step explanation:

Why if 1/6 you have to 1 x 6 in Older to get 6

6 0

3 years ago

Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$

Therefore:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30$

8 0

3 years ago

Read 2 more answers

PLEASE HELP AS SOON AS POSSIBLE

const2013 [10]

Endurance is the code word.

4 0

3 years ago

19-8c>3 what does it equal to

nadya68 [22]

Rearrange 19 × 8 × c-(3)>0

Pull out the like terms (factors) 16- 8c = -8 × (c-2)

Divide each side by. -8

Add 2 to each of the sides

So, C<2 would be your result

7 0

3 years ago

I need help with this ​

I need help with this