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3 years ago

15

Kaynard's first step in solving this rational equation is to simplify it by multiplying both sides by a common denominator. Whic

h is the simplest expression he can use to do this?

1 answer:

bulgar [2K]3 years ago

5 0

x^2 - 9 = (x + 3)(x -3)

3x - 9 = 3(x - 3)

and

6

Common denominator would be 6(x+3)(x - 3)

Answer: 6(x+3)(x - 3)

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Please take a look at the picture. Please write your answer with an explanation.

g100num [7]

Answer:

<h2><em><u>3</u></em></h2>

Step-by-step explanation:

<h3><u>Given</u><u> </u><u>question</u><u>:</u></h3>

<em>To</em><em> </em><em>simplify</em><em> </em><em>-</em><em> </em>

$14 + 16 \div {2}^{3} - (12 + {3}^{2} ) \div 7 + 2 \times ( - 5)$

<h3><u>Solution</u><u>:</u></h3>

<em>According</em><em> </em><em>to</em><em> </em><em>PEMDAS</em><em> </em><em>rule</em><em>,</em>

<em>[</em><em>First</em><em> </em><em>parenthesis</em><em>]</em>

$= 14 + 16 \div {2}^{3} - (12 + 9 ) \div 7 + 2 \times ( - 5)$

$= 14 + 16 \div {2}^{3} - 21 \div 7 + 2 \times ( - 5)$

<em>[</em><em>Then</em><em> </em><em>exponents</em><em>]</em>

$= 14 + 16 \div 8 - 21 \div 7 + 2 \times ( - 5)$

<em>[</em><em>Then</em><em> </em><em>multiplication</em><em>]</em>

= 14 + 16 ÷ 8 - 21 ÷ 7 - 10

<em>[</em><em>Then</em><em> </em><em>division</em><em>]</em>

= 14 + 2 - 3 - 10

<em>[</em><em>Then</em><em> </em><em>addition</em><em>]</em>

= 16 - 13

<em>[</em><em>Then</em><em> </em><em>subtraction</em><em>]</em>

= <em><u>3</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

8 0

3 years ago

in 3 hambare sunt 168,68 t de grau , in al doilea hambar sunt cu 2,18 t mai mult decat in primul si cu 3,78 t mai putin decat in

Lyrx [107]

Answer:

what is your language dude

4 0

3 years ago

An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.

saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

a = 10
b = 16
c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need $b^2 < a^2+c^2$ to be true in order for an acute triangle to happen.

So,

$b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5$

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

$c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\$

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0

3 years ago

A function is shown below

Scrat [10]

Answer:

13

Step-by-step explanation:

<u>Put input value instead of the x into equation and calculate the output:</u>

y = -5x - 7

<u>x = -4, then find the value of y:</u>

y = -5(-4) - 7 = 20 - 7 = 13

The output is 13 when the input is -4

6 0

2 years ago

Read 2 more answers

Brainliest to the correct answer :)

frozen [14]

Answer:

Assume that the formula is true for the (k+1)term

Step-by-step explanation:

I learned this in class a couple weeks ago in intermediate algebra

7 0

3 years ago