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vekshin1
3 years ago
7

Which represents the solution set of the inequality 5x-9 less than or equal to 21

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0
First add nine to 21. This would now make the problem 5x>30. (I don't have the less than of equal to sign on my computer but its less than or equal to in your problem) divide five on both sides. This gives you x>6.
Hitman42 [59]3 years ago
3 0
First add nine to 21. This would now make the problem 5x>30. (I don't have the less than of equal to sign on my computer but its less than or equal to in your problem) divide five on both sides. This gives you x>6.
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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

Where

(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

k = constant

From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time t = 1 \ hour, T_{(t)} = 58^{o}C

Then, we can write that

T_{(1)}=58 = -20+106 e^{k(1)}

Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

First collect like terms

58 +20 = 106 e^{k}

78 =106 e^{k}

Then,

e^{k} = \frac{78}{106}

e^{k} = 0.735849

Now, take the natural log of both sides

ln(e^{k}) =ln( 0.735849)

k = -0.30673

This is the value of the constant k

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at t = 2 \ hours

From

T_{(t)}=-20+106 e^{kt}

Then

T_{(2)}=-20+106 e^{(-0.30673 \times 2)}

T_{(2)}=-20+106 e^{-0.61346}

T_{(2)}=-20+106\times 0.5414741237

T_{(2)}=-20+57.396257

T_{(2)}=37.396257 \ ^{o}C

T_{(2)} \approxeq  37.40 \ ^{o}C

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0
2 years ago
Read 2 more answers
And I’m back lol. Or did I never leave to begin with?-
Marianna [84]

Answer:

61 is ur answer

Step-by-step explanation:

Since this was a 90 degree angle you would just subtract 29 from the 90 degrees and get your answer.

7 0
3 years ago
Find the length of a diagonal of a rectangle if the length of the rectangle is 24 cm and its width is 10 cm. A) 22 cm B) 26 cm C
Alik [6]
Your answers are
1.B
2.D
3.A
3 0
3 years ago
Read 2 more answers
What type of line is PQ?<br> A. altitude<br> B. angle bisector<br> C. side bisector<br> D. median
frosja888 [35]

Answer:

altitude

hope that helps ✌

8 0
3 years ago
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A line that includes the point (4,1) has a slope of 1 7 . What is its equation in point-slope form?
Sergeeva-Olga [200]

Answer:

y = 17x-67

Step-by-step explanation:

The one point form of line also called slope point form is given by

(y-y_1)=m(x-x_1)

where (x1, y1) is the point and m is slope

Given: (x1, y1) = (4,1) and m= 17

Substituting these values in above equation to find equation in point-slope form

(y-1)=17(x-4)

y-1 = 17x-68

y = 17x-67

the point -slope form of equation y = 17x-67

5 0
2 years ago
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