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Anit [1.1K]
3 years ago
7

The expression 3r - 6 can be written as _____. 3(r - 2) 3(r - 6) 3(3r - 6) user: 18 - 2[x (x - 5)] user: simplify 18 - 2[x (x -

5)]. user: simplify 18 - 2[x (x - 5)]. 8 - 4x 28 - 4x 28 - 2x
Mathematics
1 answer:
Vlada [557]3 years ago
4 0
The expression 3r - 6 can be written as 3(r-2), because when you distribute 3(r-2) you get 3r -6. So they are equivalent.  
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For } (x) = 4x+1 and g(x) = x2 -5, find (f/g)(x)
matrenka [14]

Answer:

Step-by-step explanation:

                                                           4x + 1

The quotient   (f/g)(x) is    (f/g)(x) = ---------------

                                                          x^2 - 5

Note that x^2 means "square of x," whereas "x2" is ambiguous.

7 0
2 years ago
How do you write (243)^ 3/5 in radical form? THEN simplified?! *PLEASE HELP
SOVA2 [1]

Answer:

27

Step-by-step explanation:

If you have an exponent that is a fraction, you need to make a radical with the index from the denominator and an exponent of the radicand from the numerator.

(243)^3/5=(\sqrt[5]{243}^3)

This would come out as \sqrt[5]{14348907^}. this further simplifies down to the final answer of 27

6 0
3 years ago
Forty students are In Science club. Of those 45% are girls. This percent increase 56% after new girls join the club. How many ne
stepan [7]
45% of 40 is 0.45×40=18 girls
if x girls join then 56% of 40+x is 0.56(40+x)=18+x
22.4+0.56x=18+x
put together like terms
4.4=0.44x
<span>x=10 girls joined</span>
8 0
3 years ago
For a 4-unit class like Statistics, students should spend average of 12 hours studying for the class. A survey was done on 24 st
Zanzabum

Answer:

a) 68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 13 hours

Standard deviation = 2.8 hours.

a) 68% of the students spend between hours and hours on Statistics each week.

Within 1 standard deviation of the mean.

13 - 2.8 = 10.2 hours

13 + 2.8 = 15.8 hours

68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between hours and hours on Statistics each week.

Within 2 standard deviations of the mean

13 - 2*2.8 = 7.4 hours

13 + 2*2.8 = 18.6 hours

95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between hours and hours on Statistics each week.

Within 3 standard deviations of the mean

13 - 3*2.8 = 4.6 hours

13 + 3*2.8 = 21.4 hours

99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

8 0
3 years ago
61/18 in simples form
Orlov [11]
\frac{61}{18} is in the simplest form it can be since 61 is a prime number.
6 0
3 years ago
Read 2 more answers
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