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2 years ago

-5(t + 3)= -30 Solve for the variable!! Please

Mathematics

1 answer:

kvv77 [185]2 years ago

4 0

Answer:

$\huge\boxed{t=3}$

Step-by-step explanation:

$-5(t+3)=-30$

<h3>METHOD 1:</h3>

$-5(t+3)=-30$ divide both sides by (-5)

$\dfrac{-5\!\!\!\!\diagup(t+3)}{-5\!\!\!\!\diagup}=\dfrac{-30}{-5}$

$t+3=6$ subtract 3 from both sides

$t+3-3=6-3\\t=3$

<h3>METHOD 2:</h3>

$-5(t+3)=-30$ use the distributive property a(b + c) = ab + ac

 $(-5)(t)+(-5)(3)=-30$ 

 $-5t-15=-30$  add 15 to both sides

$-5t-15+15=-30+15$

$-5t=-15$ divide both sides by (-5)

$\dfrac{-5t}{-5}=\dfrac{-15}{-5}\\\\t=3$

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Step-by-step explanation:

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2 years ago

List the coordinates of FOUR vertices that create the feasible region on the graph. Submit your answer in the form of FOUR order

hoa [83]

Answer:

The coordinates of the vertices are;

(200, 200), (300, 200), (300, 0), (0, 500)

Step-by-step explanation:

The vertices are the corners of a polygon. It is the point where an angle is formed by the intersection of two lines

The feasible region is the solution space of the points of the variables that meet the specification of the problem set by means of a constant or the definition of inequalities or equations

From the graph of the function of inequalities, we have that the four vertices are the four points where the lines bounding the area of the feasible region of the inequalities meet

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3 years ago

The graph of the function showing the path of a soccer ball thrown by a goalie in a video game, f(x) = –0.05x2 + 2.5x + 5.2, is

Tju [1.3M]

Answer:

The correct option is 4.

Step-by-step explanation:

The given function is

$f(x)=-0.05x^2+2.5x+5.2$

Where f(x) is height of the ball and x is the distance.

It is a polynomial function with degree 2. All polynomial functions are defined for all real numbers, therefore the mathematical domain of the function is all real numbers.

$-\infty$

Factorize the given function.

$f(x)=-0.05(x^2-50x-104)$

$f(x)=-0.05(x^2-52x+2x-104)$

$f(x)=-0.05(x(x-52)+2(x-52))$

$f(x) = -0.05 (x - 52) (x + 2)$

Put f(x)=0 to find the x intercepts.

$0 = -0.05 (x - 52) (x + 2)$

Equate each factor equal to 0.

$x=52,-2$

Therefore at x=52 and -2, the graph of f(x) intersects x-axis. Before x=-2 and after x=52 the values of f(x) is negative. Height cannot be negative, therefore reasonable domain is lie between -2 to 52.

Distance cannot be negative, therefore the reasonable domain must be positive.

$0\leq x\leq 52$

Therefore the reasonable domain is $0\leq x\leq 52$ and option 4 is correct.

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2 years ago