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juin [17]
4 years ago
8

An empty box weighs 2 and 1/4 pounds. It is then filled with 16 and 2/3 pounds of fruit. What is the weight of the box when it i

s full ?
Mathematics
1 answer:
Anettt [7]4 years ago
8 0

Given that an empty box weighs 2 and 1/4 pounds.

Weight of the fruit is 16 and 2/3 pounds.

Weight of filled box means total weight of box and the fruit.

So we will add both values.

2 and 1/4 pounds+ 16 and 2/3 pounds

= 2 + 1/4 + 16 + 2/3 pounds

= 2 + 16 + 1/4 + 2/3 pounds

= 18 + 1/4 + 2/3 pounds

= 18 + \frac{1}{4}+\frac{2}{3} \; pounds

= 18 + \frac{1*3}{4*3}+\frac{2*4}{3*4} \; pounds

= 18 + \frac{3}{12}+\frac{8}{12} \; pounds

= 18 + \frac{3+8}{12} \; pounds

= 18 + \frac{11}{12} \; pounds

Hence final answer is 18 and 11/12 pounds.

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Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5
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Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

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Step-by-step explanation:

Given

  • \left(x_1,\:y_1\right)=\left(-5,5\right)
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Point-Slope Form equation is

\left(y-y_1\right)=m\left(x-x_1\right)

\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

y-5=\frac{-8}{5}\left(x+5\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

y-5=-\frac{8}{5}\left(x+5\right)

y-5+5=-\frac{8}{5}\left(x+5\right)+5

y=-\frac{8}{5}x-3

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                           y=-\frac{8}{5}x-3

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