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juin [17]
3 years ago
8

An empty box weighs 2 and 1/4 pounds. It is then filled with 16 and 2/3 pounds of fruit. What is the weight of the box when it i

s full ?
Mathematics
1 answer:
Anettt [7]3 years ago
8 0

Given that an empty box weighs 2 and 1/4 pounds.

Weight of the fruit is 16 and 2/3 pounds.

Weight of filled box means total weight of box and the fruit.

So we will add both values.

2 and 1/4 pounds+ 16 and 2/3 pounds

= 2 + 1/4 + 16 + 2/3 pounds

= 2 + 16 + 1/4 + 2/3 pounds

= 18 + 1/4 + 2/3 pounds

= 18 + \frac{1}{4}+\frac{2}{3} \; pounds

= 18 + \frac{1*3}{4*3}+\frac{2*4}{3*4} \; pounds

= 18 + \frac{3}{12}+\frac{8}{12} \; pounds

= 18 + \frac{3+8}{12} \; pounds

= 18 + \frac{11}{12} \; pounds

Hence final answer is 18 and 11/12 pounds.

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Suppose you are interested in the effect of skipping lectures (in days missed) on college grades. You also have ACT scores and h
DIA [1.3K]

Answer:

a) For this case the intercept of 2.52 represent a common effect of measure for any student without taking in count the other variables analyzed, and we know that if HSGPA=0, ACT= 0 and skip =0 we got colGPA=2.52

b) This value represent the effect into the ACT scores in the GPA, we know that:

\hat \beta_{ACT} = 0.015

So then for every unit increase in the ACT score we expect and increase of 0.015 in the GPA or the predicted variable

c) If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_i = 0

Alternative hypothesis: \beta_i \neq 0

Or in other wouds we want to check if an specific slope is significant.

The significance level assumed for this case is \alpha=0.05

Th degrees of freedom for a linear regression is given by df=n-p-1 = 45-3-1 = 41, where p =3 the number of variables used to estimate the dependent variable.

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_i}{SE_{\beta_i}}

And replacing we got:

t = \frac{-0.5}{0.0001}=-5000

And for this case we see that if we find the p value for this case we will get a value very near to 0, so then we can conclude that this coefficient would be significant for the regression model .

Step-by-step explanation:

For this case we have the following multiple regression model calculated:

colGPA =2.52+0.38*HSGPA+0.015*ACT-0.5*skip

Part a

(a) Interpret the intercept in this model.

For this case the intercept of 2.52 represent a common effect of measure for any student without taking in count the other variables analyzed, and we know that if HSGPA=0, ACT= 0 and skip =0 we got colGPA=2.52

(b) Interpret \hat \beta_{ACT} from this model.

This value represent the effect into the ACT scores in the GPA, we know that:

\hat \beta_{ACT} = 0.015

So then for every unit increase in the ACT score we expect and increase of 0.015 in the GPA or the predicted variable

(c) What is the predicted college GPA for someone who scored a 25 on the ACT, had a 3.2 high school GPA and missed 4 lectures. Show your work.

For this case we can use the regression model and we got:

colGPA =2.52 +0.38*3.2 +0.015*25 - 0.5*4 = 26.751

(d) Is the estimate of skipping class statistically significant? How do you know? Is the estimate of skipping class economically significant? How do you know? (Hint: Suppose there are 45 lectures in a typical semester long class).

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_i = 0

Alternative hypothesis: \beta_i \neq 0

Or in other wouds we want to check if an specific slope is significant.

The significance level assumed for this case is \alpha=0.05

Th degrees of freedom for a linear regression is given by df=n-p-1 = 45-3-1 = 41, where p =3 the number of variables used to estimate the dependent variable.

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_i}{SE_{\beta_i}}

And replacing we got:

t = \frac{-0.5}{0.0001}=-5000

And for this case we see that if we find the p value for this case we will get a value very near to 0, so then we can conclude that this coefficient would be significant for the regression model .

7 0
3 years ago
Please help me with this problem please?
Alex

Answer:

Lily would spend on each type of activity would be 222 minutes.

Step-by-step explanation:

7 0
2 years ago
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find the x-intercepts of the parabola with vertex(6,27) and y-intercept (0,-81). write answer in form (x1,y1)(x2,y2). if necessa
sergey [27]
The vertex form of the equation is:
y = a ( x - h )² + k
- 81 = a ( 0 - 6 )² + 27
- 81 = 36 a + 27
- 108 = 36 a
a = - 108 : 36
a = - 3
y = - 3 ( x - 6 )² + 27
y = - 3 ( x² - 12 x + 36 ) + 27
y = - 3 x² + 36 x - 108 + 27
y = - 3 x² + 36 x - 81
y = - 3 ( x² - 12 x + 27 )
x² - 12 x + 27 = 0
x² - 9 x - 3 x + 27 = 0
x ( x - 9 ) - 3 ( x - 9 ) = 0
( x - 9 ) ( x - 3 ) = 0
x 1 = 3,  x 2 = 9
Answer:
The x-intercepts are ( 3, 0 ) and ( 9, 0 ).
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3 years ago
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1.4t - 0.4 (t- 3.1) =5.8
GenaCL600 [577]
1 Expand
1.4t-0.4t+1.24=5.8

2 Simplify 1.4t-0.4t+1.241.4t−0.4t+1.24 to t+1.24t+1.24
t+1.24=5.8

3 Subtract 1.241.24 from both sides
t=5.8−1.24

4 Simplify 5.8-1.245.8−1.24 to 4.564.56
t=4.56
7 0
3 years ago
PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
Crazy boy [7]

Answer:

between one and 6

Step-by-step explanation:

musrbe the answer

6 0
3 years ago
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