Answer:
600
Step-by-step explanation:
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer: 5.5km
Step-by-step explanation:
The scale given 1 : 25 000 , and it was said that on the map , the distance between two railway stations is 22 cm , this means that the scale of the map is 1: 25000 cm.
The scale 1 : 25 000 means that each centimeters on the map represent 25 ,000 in real life ,therefore , to calculate the real distance between the two railway station , we have
25,000 X 22
= 550000 cm
To convert this to km
Recall that
1 km = 100,000 cm
Therefore we will divide the answer by 100,000 , that is
550000/100000
= 5.5 km
Therefore , the real distance between the two railway stations is 5.5km
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Answer:
Step-by-step explanation:
Given
Required
Select 3 equivalent expressions
Express 9 as 3^2
--- This is one equivalent expression
Take 
as difference of two squares
-- This is another equivalent expression:
Solving further:
becomes
-- This is another equivalent expression:
Hence, the equivalent expressions are:
