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katrin2010 [14]

3 years ago

7

An unknown gas effuses at a rate 0.797 times that of nitrogen at the same temperature. what is the molar mass of the unknown gas

?

2 answers:

kicyunya [14]3 years ago

7 0

<span>mass B/molar mass A = (rate A/rate B)^2. we know our unknown gas (A) effuses at .797 times our known gas (B) so rate A/rate B = .797 so 0.797^2 = 28 / molar mass A Molar mass A = 28 / 0.635 = 44.09 g / mole Molar mass is 44.09 g/mol</span>

kramer3 years ago

5 0

Answer: Molar mass of unknown gas=43.75 $gmol^{-1}$

Explanation: Graham's Law states that the rate of effusion of gas is inversely proportional to the square root of their atomic masses.

${\text {Rate of effusion}}=\frac{1}{\sqrt\text {Molecular mass}}$

$\frac{R_1}{R_2}=\sqrt\frac{M_2}{M_1}$

$R_1$ = rate of effusion of nitrogen = x

$R_2$ = rate of effusion of unknown gas = 0.797x

$M_1$ = Molecular mass of nitrogen $(N_2)$ = 28g

$M_2$ = Molecular mass of unknown gas

$\frac{x}{0.797x}=\sqrt\frac{M_2}{28gmol^{-1}}$

$M_2=43.75gmol^{-1}$

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