Answer:
Explanation:
6.90 mol x grams
2As + 6NaOH = 2Na3AsO3 + 3H2
6 mol 2 mol
192 g/mol
6.90 mol NaOH x 2 mol Na3AsO3/6 mol NaOH== 2.3 mol Na3AsO3
2.3 mol Na3AsO3 x 192 g/mol = 442 g Na3AsO3
Barium, it's an earthy alkaline metal it's atomic number is 56
True. because a theory has facts.
What atomic model. Please provide more info when you ask a question.
Answer:
CoCl₃ > Li₂SO₄ > NH₄I.
Explanation:
- Adding solute to water causes depression of the boiling point.
- The elevation in boiling point (ΔTf) can be calculated using the relation:
<em>ΔTf = i.Kf.m,</em>
where, ΔTf is the depression in freezing point.
i is the van 't Hoff factor.
- <em>van 't Hoff factor</em><em> is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.</em>
Kf is the molal depression constant of water.
m is the molality of the solution.
<u><em>(1) Li₂SO₄:</em></u>
i for Li₂SO₄ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.
∴ ΔTb for (Li₂SO₄) = i.Kb.m = (3)(Kf)(m) = 3(Kf)(m).
<u><em>(2) NH₄I:</em></u>
i for NH₄I = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.
∴ ΔTb for (NH₄I) = i.Kb.m = (2)(Kf)(m) = 2(Kf)(m).
<u><em>(3) CoCl₃:</em></u>
i for CoCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.
∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(m) = 4(Kf)(m).
- <em>So, the ranking of the freezing point from the highest to the lowest is:</em>
CoCl₃ > Li₂SO₄ > NH₄I.
