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3 years ago

Help me please Can someone help me and explain how to find the configuration pleasee

Chemistry

1 answer:

iogann1982 [59]3 years ago

3 0

The numbers in the powers are the number of electrons in a specific orbital. so you can add them to find the atomic number

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Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty

anastassius [24]

Answer :

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression of $HC_2H_3O_2$ will be:

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression of $Co(H_2O)_6^{3+}$ will be:

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression of $CH_3NH_3^+$ will be:

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

3 0

3 years ago

How many moles of water are in 1/4 cup of water

il63 [147K]

Answer:

3.4752 moles of water

Explanation:

There are 13.84 mole in one cup of water so,

13.84 divided by 4= 3.4725 :)

5 0

3 years ago

Read 2 more answers

creativ13 [48]

A.chloroplast
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6 0

3 years ago

Read 2 more answers

Magnesium element has three isotopes: 24Mg, 25Mg, and 26Mg. The natural abundance of the isotopes on Earth is 78.99% 24Mg with a

Dafna11 [192]

Answer:

24.305 to the nearest thousandth.

Explanation:

That is 0.7899*23.985 + 0.10* 24.985+0.1101*25.9825

= 24.305.

3 0

4 years ago

when 824 J of heat is added to 9 grams of oil at 30°c , the temperature increases to 87°C. what is the specific heat of the oil

sattari [20]

Answer:

c = 1.61 j/g.°C

Explanation:

Given data:

Mass of oil = 9 g

Heat added = 824 j

Initial temperature = 30°C

Final temperature = 87°C

Specific heat of oil = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - final temperature

ΔT = 87°C - 30°C

ΔT = 57 °C

Q = m.c. ΔT

824 j = 9 g × c × 57 °C

824 j = 513 g. °C × c

c = 1.61 j/g.°C

5 0

3 years ago