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Afina-wow [57]
3 years ago
10

2x-5y=11 4x+10y=18 elimination

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0
2x-5y=11(multiply all by -2. turns into. -4x+10y=-22). -4x+10y=-22. 4x+10(-7.5)=18
4x+10y=18. 4x-75=18
20y=-4. 4x=75+18
y=-7.5. x=23.25
Answer) (23.25, 7.5)
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Match each question to the correct problem.
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<h2>Answer:</h2>

<em>(Check attached images).</em>

<h2>Step-by-step explanation:</h2>

<h3>Exercise 1.</h3>

a. Convert to decimals.

To order the numbers from least to greaters, convert them to decimals and compare.

5.2(percent)=0.052\\ \\\frac{1}{7} =0.1429\\\\ -0.8=-0.8000\\ \\\frac{-11}{5} =-2.2

b. Select the second least number.

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<h3>Exercise 2.</h3>

a. Convert to decimals.

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b. Select the correct number.

-\frac{1}{5}.

<h3>Exercise 3.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

<em>59%=0.59</em>

<em>3/5=0.6</em>

<em />

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<h3>Exercise 4.</h3>

a. Convert to decimals.

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b. Conclude.

Seeing that -3.5% is less than -0.35, the symbol that makes the statement true is ">".

<h3>Exercise 5.</h3>

a. Try to visually estimate b.

B appears to have a value of -0.9.

b. Convert the numbers to decimals.

-3.4%= -0.034

-0.031

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c. Select the correct answer.

<em>Since we estimated the value of b as -0.9, the number that best adequates to its value is </em>-\sqrt{0.8}.

<h3>Exercise 6.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

5.2%= 0.052

1/7= 0.1429

b. Select the correct number.

5.2% is the second largest.

<h3>Exercise 7.</h3>

a. Convert to decimals.

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b. Select the correct answer.

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<h3>Exercise 8.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the negative numbers.</em>

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