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Andrews [41]
2 years ago
5

Find the least common denominator

a1" title="\frac{3}{9} \frac{8}{4}" alt="\frac{3}{9} \frac{8}{4}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
8 0

Answer:

36 is your least common denominator. Hope this helps

Step-by-step explanation:

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Find the measure of ∠EGC. Circle A with chords EF and CD that intersect at point G, the measure of arc EC is 50 degrees, the mea
miv72 [106K]

Answer:

m∠EGC=70°

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite

so

m∠EGC=(1/2)[arc EC+arc DF]

<u><em>Find the value of x</em></u>

we have

m∠EGC=(7x+7)°

arc EC=50°

arc DF=10x°

substitute and solve for x

(7x+7)°=(1/2)[50°+10x°]

14x+14=50+10x

14x-10x=50-14

4x=36

x=9

<u><em>Find the measure of angle EGC</em></u>

m∠EGC=(7x+7)°

substitute the value of x

m∠EGC=(7(9)+7)°=70°

8 0
4 years ago
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Solve for x, full steps
xxMikexx [17]

Answer:

x =34.56°

Step-by-step explanation:

adjacent/ hypotenuse =cosx

cosx = 14/17

x = cos^{-1}(14/17)

x =34.56°

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3 years ago
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Which skier will have a greater potential energy? Skier one is higher then skier two.
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Skier one will have more potential energy
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Which angles are vertical angles and, therefore, congruent?
ch4aika [34]

Answer:

A and F

Step-by-step explanation:

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4 years ago
What is the slope of a line perpendicular to the line whose equation is 5x - y = -7.
BARSIC [14]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

5x-y=-7\implies 5x-y+7=0 \\\\\\ \stackrel{\stackrel{m}{\downarrow }}{5} x+7=y\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so a line perpendicular to that one above will have a slope of

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{5\implies \cfrac{5}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{5}}}

3 0
2 years ago
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