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choli [55]
2 years ago
10

Help please what is the ratio

Mathematics
1 answer:
siniylev [52]2 years ago
3 0

It’s a 1:7 because the total number of girls is 14, and the number of redheads are 2, giving you the ratio of 2:14, but if you take it into the lowest terms, the final answer is 1:7.

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The sum of the measures of the angles of any triangle is 180°. In triangle ABC, angles A and B have the same measure, while the
lesya [120]

This is the solution

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4 0
2 years ago
Write the prime factorization of 18. Use exponents when appropriate and order the factors from least to greatest (for example, 
Vsevolod [243]
Prime factorization is when the numbers are divided until they cannot be divided anymore.

For example, the number 18.

18/2 = 9

9/3 = 3

So the prime factorization is 2,3,3

As it says use exponents: There are 2 threes. 3 x 3 is the same as 3²

3² x 2 should be your answer

hope this helps
5 0
3 years ago
Solve equation 2x+3=2x
Digiron [165]
This is an impossible equation.

If you have something and you add 3 to it, how can the result be the same as the original?
3 0
3 years ago
What is the rate of change of the perimeter of the square at the instant the area is 49 m2?
vagabundo [1.1K]
Let x = the length of a side of the square (m).
The area is
A = x²
The perimeter is
P =  4x

The rate of change of P with respect to x is
P'(x) = 4  (independent of x)

When A = 49 m², then x = 7 m.
The rate of P is 4.

Answer: 4
6 0
3 years ago
Simplify
Diano4ka-milaya [45]

Answer:

\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}

Step-by-step explanation:

16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}

=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}

5 0
3 years ago
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