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trasher [3.6K]
3 years ago
13

3(у - 3) - 2(у 4) = 4​

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
3 0

Answer:

y = 5

Step-by-step explanation:

3(у - 3) - 2(у -4) = 4​

Distribute

3y -9 -2y +8 =4

Combine like terms

y -1 =4

Add 1 to each side

y-1+1 = 4+1

y = 5

Wewaii [24]3 years ago
3 0

Answer:

y = 5

Step-by-step explanation:

So I'm gonna assume this is 3(y-3) - 2(y-4) = 4

Use the distributive property

3y - 9 - 2y + 8 = 4

y - 1 = 4

y = 5

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Answer:

40

Step-by-step explanation

34 divided by 85 times 100 equals 40

plz mark me as brainliest :)

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3 years ago
Here are two number machines, A and B.
Troyanec [42]

Answer:

Step-by-step explanation:

We can write them both like functions like this

Where

x=input

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B=Output B

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2 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
3 years ago
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zimovet [89]

Answer:

Your answer is B

Step-by-step explanation:

Take 300 and subtract it by 99 you'll get 201

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Which is why your answer is B!




Hope this helps! -Queenb369


(P.S, If you could give me the brainlist if i'm right, that will be great thanks!)


6 0
3 years ago
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