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3 years ago

Brad cuts a triangular prism with a plane parallel to the base of the prism what will the shape of the cross section be?

Mathematics

2 answers:

devlian [24]3 years ago

4 0

the answer will be triangular/

Hope I helped. Mark as brainliest

juin [17]3 years ago

4 0

Type of prism is decided by the name of base. Like it can be triangular, square, pentagon etc.

Given that prism is triangular so that means it's base is a triangle.

Given that Brad cuts the given triangular prism with a plane parallel to the base of the prism.

Now we have to find the shape of the cross section of that plane.

It is obvious that the plane obtaind after cutting the ptrism parallel to the base will be of same shape as base.

Hence required plane will be a triangle.

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The cost c, for manufacturing x flags is given by c=x? -24x +39. Find the number of flags manufactured if the cost is $120.

IRINA_888 [86]

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Answer:

Step-by-step explanation:

You want to find x when c = 120.

120 = x^2 -24x +39

x^2 -24x -81 = 0 . . . . . . subtract 120 to put in standard form

(x -27)(x +3) = 0 . . . . . .factor it

Solutions are ...

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The number of flags manufactured for a cost of $120 is 27 flags.

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2 years ago

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stiks02 [169]

Answer:

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Step-by-step explanation:

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2 years ago

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Step2247 [10]

1.9

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2 years ago

What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in

elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

Solution:

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

The area of triangle when hypotenuse and length of one side of triangle is given:

$A = \frac{1}{2} a \sqrt{c^2 - a^2}$

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

$A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}$

$A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727$

Thus area of triangle is 12.727 square inches

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2 years ago

Find the area of the regular polygon 10, 4

Afina-wow [57]

With all the given context, I would assume it’s length times width, which would give us an answer of 40 :) hope this helped !

3 0

1 year ago