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3 years ago

6. Nicole deposits $2,136 in a såvings account paying 5% interest rate. To the

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

8 0

Answer: $3,166

Step-by-step explanation:

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PLEASE HELP

alina1380 [7]

When the dice is rolled 14 times then from the given data the probability of 1,2,3,4,5,6 is 3/14,1/14,4/14,1/14,3/14,2,14.

Given Roll of dice and outcomes from 1 to 14 is 1,3,5,4,5,3,3,1,3,5,6,1,6,2.

From the given collected data we can find out number of times each number came when the dice is rolled.

Number of times 1 came=3

Number of times 2 came=1

Number of times 3 came=4

Number of times 4 came=1

Number of times 5 came=3

Number of times 6 came=2

The probabilities are in fraction form:

P(1)=3/14

P(2)=1/14

P(3)=4/14

P(4)=1/14

P(5)=3/14

P(6)=2/14

The probabilities in decimal form:

P(1)=0.21

P(2)=0.07

P(3)=0.28

P(4)=0.07

P(5)=0.21

P(6)=0.14

The probabilities in percentage:

P(1)=21%

P(2)=7%

P(3)=28%

P(4)=7%

P(5)=21%

P(6)=14%

Hence the probabilities are 3/14,1/14,4/14,1/14,3/14,2,14.

Learn more about probabilities here brainly.com/question/24756209

#SPJ10

5 0

2 years ago

How many 1/100 are in 3/10

RUDIKE [14]

<span>How many 1/100 are in 3/10

multiply by 10 for both numerator and denominator
3/10 = 30/100

Ans: 30

So that there are 30 1/100 in 3/10</span>

6 0

4 years ago

-1/2(10x + 2) - 7 = -x - 4

xxTIMURxx [149]

The answer would be -1. ☺️

7 0

3 years ago

Read 2 more answers

Which statement is correct?

Anika [276]

$3\frac{5}{8} =3.625
\\ \\3.6$

8 0

4 years ago

A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At

kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

(a) So, the probability of B,

$P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

$\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}$

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

$\implies P(A\cap B\cap C)=\frac{1}{8}$

7 0

3 years ago