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3 years ago

What is 20 times 20plz tell me

Mathematics

1 answer:

vladimir1956 [14]3 years ago

8 0

Answer:

400

Step-by-step explanation:

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Question 2:

Helga [31]

Answer:

15mins

Step-by-step explanation:

Given that he worked out a total of 360mins, and jogged 45mins/day:

$Jog \ Time=Total \ Time- Bike \ Time\\=360-(45\times6)\\=90min$

Therefore, Allen jogged a total of 90mins in the past one week. To calculate the time jogged each day, we divide the total jog time by number of days jogged:

$t_d=Total \Time/(No \of \ Days)\\=90/6\\=15mins$

Allen jogged 15mins per day.

6 0

3 years ago

Los puntos de intersección de los gráficos de f(x)=x2+6x−7 y g(x)=4x−10

alisha [4.7K]

Answer:

Those graphs do not intersect.

Estes gráficos no se intersecciónan

Step-by-step explanation:

The intersection points are x for which:

$f(x) = g(x)$

In this question:

$f(x) = x^{2} + 6x - 7$

$g(x) = 4x - 10$

$x^{2} + 6x - 7 = 4x - 10$

$x^{2} + 2x + 3 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$x^{2} + 2x + 3 = 0$

So $a = 1, b = 2, c = 3$

$\bigtriangleup = b^{2} - 4ac = 2^{2} - 4*1*3 = -8$

Sincce $\bigtriangleup$ is negative, there are no solutions, which means that those graphs do not intersect.

7 0

3 years ago

Solve for x 1/2+4/2x=x+4/10

Ksivusya [100]

$\frac{1}{2}$ + $\frac{4}{2}$ x =x + $\frac{4}{10}$
$\frac{1}{2}$ +2x=x+ $\frac{2}{5}$
subtract x from each side
$\frac{1}{2}$ + x= $\frac{2}{5}$
now subtract $\frac{1}{2}$ from each side
x= -0.1

Hope I could help

7 0

3 years ago

Read 2 more answers

1. Parallelogram ABCD is similar to

ss7ja [257]

Answer:

The length of GH is 2 inches

Step-by-step explanation:

The given parameters are;

Parallelogram ABCD ~ Parallelogram EFGH

Segment BC of parallelogram ABCD corresponds to segment FG of parallelogram EFGH

Similarly

Segment CD of parallelogram ABCD corresponds to segment GH of parallelogram EFGH

In parallelogram ABCD, we have;

Segment BC = 21 in.

Segment CD = 6 in.

In parallelogram ABCD, we have;

Segment FG = 7 in.

Given that parallelogram ABCD is similar to parallelogram EFGH, we have;

$\dfrac{\overline{BC}}{\overline{FG}} = \dfrac{\overline{CD}}{\overline{GH}}$

Which by substitution, gives;

$\dfrac{21}{7} = 3 = \dfrac{6}{\overline{GH}}$

$\therefore \overline{GH} = \dfrac{6}{3} = 2$

$\overline{GH}$ = 2 inches

8 0

3 years ago

A used-car dealer has a vehicle on the lot with a sticker price of $5999. If the

Digiron [165]

Answer:

$4999

Step-by-step explanation:

Let the cost of the car be x

Then considering 20% markup, the sticker price is:

x + 20% = 5999

Since 20% of x is 20/100x = 0.2x,

x+ 0.2x = 5999
1.2x = 5999
x = 5999/1.2
x ≈ $4999

So dealer paid $4999 for the car

3 0

3 years ago