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vodomira [7]
4 years ago
13

a toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.

Mathematics
1 answer:
satela [25.4K]4 years ago
7 0

A toy cost 0.85p in January.

Step-by-step explanation:

Given,

Mark down in January = 15%

Let,

Price in December = p

Mark down in January = 15% of price in December

Mark down in January = \frac{15}{100}*p

Mark down in January = 0.15p

Price of toy in January = Price in December - Mark down

Price of toy in January = p - 0.15p = 0.85p

A toy cost 0.85p in January.

Keywords: mark down, subtraction

Learn more about subtraction at:

  • brainly.com/question/1993757
  • brainly.com/question/2048256

#LearnwithBrainly

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<h3><u>Question</u> :-</h3>

Is (x-2) is a factor of x³-3x²-x +7 –

  • Yes
  • No ☑

<h3><u>Explanation</u> :-</h3>

We are given –

  • Polynomial function, P(x) = x³-3x²-x +7

  • In order to check if x - 2 is a factor of x³-3x²-x +7 or not, we must show that P(2) = 0.

  • Let's find value of x!

\qquad \twoheadrightarrow\bf P(x) = x³-3x²-x +7

\qquad \twoheadrightarrow\bf Q(x) =x - 2

\qquad \twoheadrightarrow\bf If \:Q(x) = 0

\qquad \twoheadrightarrow\bf x - 2 = 0

\qquad \twoheadrightarrow\bf x = 2

Now Put x = 2 into the polynomial –

\qquad \purple{\twoheadrightarrow\bf P(2) = 2³-3(2)²-2+7}

\qquad \twoheadrightarrow\sf P(2) = 8 - 3 \times 4 +5

\qquad \twoheadrightarrow\sf P(2) = 8 -12 +5

\qquad \twoheadrightarrow\sf P(2) = 13-12

\qquad \purple{\twoheadrightarrow\bf P(2) =1 }

  • Since the value of the polynomial function st x = 2 is not Zero (0). Henceforth, ( x - 2) is a factor of  x³-3x²-x +7.

________________________________________

5 0
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