Answer:
square root of 25, 2.51, 5/2, 0.25, 10^-1, -2.5%
Step-by-step explanation:
when in the same form they are
5, 2.51, 2.5, .025, 0.1, -0.025
Answer:
P(2) = 4
Step-by-step explanation:
P(X) = -2X4 + 4X3 - X + 6
Use the remainder theorem to find quotient and remainder and the value of P(2)
First add in any missing exponents: P(x) = -2x4 + 4x3 + 0x2 -x + 6
Write all the coefficients in a line (including the constant) with the number being solved for off to the left:
Bring down the first coefficient (-2), multiply it by the term in question (2), carry the product up under
the 2nd coefficient and then add down (4-4=0), carry up the sum and repeat process across. The last
sum is the answer for P(2)
(2) -2 4 0 -1 6
-4 0 0 -2
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-2 0 0 -1 4
P(2) = 4
check the answer: P(2) = -2(24) + 4(23) -2 + 6 = -2(16) +4(8) + 4 = 4 Our answer is correct
The quotient is what we would bet by dividing the original equation by the polynomial (x-2). The
answer is given by the bottom numbers which will begin an one lower exponent than the original.
Quotient is: -2x3 + 0x2 + 0x -1 = 2x3 - 1
The remainder is: 4/(x-2)
Solution:
subtracting 0.9 and 9 from both side
it will become
subtracting 1.8 from both side
it will become
now dividing both side by 3.5
So
which means
Hope it helps!
General formula for n-th term of arithmetical progression is
a(n)=a(1)+d(n-1).
For 3d term we have
a(3)=a(1) +d(3-1), where a(3)=7
7=a(1)+2d
For 7th term we have
a(7)=a(1) +d(7-1)
a(7)=a(1) + 6d
Also, we have that the <span>seventh term is 2 more than 3 times the third term,
a(7)=3*a(3)+2= 3*7+2=21+2=23
So we have, </span>a(7)=a(1) + 6d and a(7)=23. We can write
23=a(1) + 6d.
Now we can write a system of equations
23=a(1) + 6d
<span> - (7=a(1)+2d)
</span>16 = 4d
d=4,
7=a(1)+2d
7=a(1)+2*4
a(1)=7-8=-1
a(1)= - 1
First term a(1)=-1, common difference d=4.
Sum of the 20 first terms is
S=20 * (a(1)+a(20))/2
a(1)=-1
a(n)=a(1)+d(n-1)
a(20) = -1+4(20-1)=-1+4*19=75
S=20 * (-1+75)/2=74*10=740
Sum of 20 first terms is 740.
The short answer is trial and error. The side lengths "3" and "4" can both be substituted for a² and b² but not c² because their value squared is not high enough since 5² is 25. "c²" as to match the longest side because the smaller numbers will cause the equation to not be true. See Below.
a² + b² = c²
3² + 4² = 5²
9 + 16 = 25
25 = 25
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a² + b² = c²
4² + 3² = 5²
16 + 9 = 25
25 = 25
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a² + b² = c²
5² + 4² = 3²
25 + 16 = 9
41 ≠ 9
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a² + b² = c²
3² + 5² = 4²
9 + 25 = 16
34 ≠ 16
Hope this helped!
