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3 years ago

HURRY!!!!!!!!! PLS!!!!!!!

Mathematics

1 answer:

nata0808 [166]3 years ago

7 0

Answer:

the answer is 7

Step-by-step explanation:

im not that sure on why its not there but i did it three times and sill got 7:(

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The cost, C(x),for manufacturing x units of certain product Is given byC(x)=x^2-20x+35, find the units manufactured at a cost of

Rainbow [258]

Answer:

No units

Step-by-step explanation:

The cost function is given by;

$C(x)=x^2-20x+35$

To find the units manufactured at a cost of $5,560

We equate the C(x) to 5560 and solve for x.

$x^2-20x+35 = 5560$

$x^2-20x+35 - 5560 = 0$

$x^2-20x - 5525= 0$

The discriminant of this equation is negative.

That is,

$d = {( - 20)}^{2} - 4 \times 1 \times - 5560 \: < 0$

Hence the equation has no real roots.

This means no units can be produced at $5,560

7 0

3 years ago

X+2 X-2 2x+y x + 1 what’s the answer

icang [17]

Answer:

( 3x - 2, 2x ± yx ) ± 1

Step-by-step explanation:

5 0

3 years ago

Can someone help me with finding the slope of the graph- ONLY GRAPH

Alinara [238K]

Answer:

m = - 2

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

5 0

3 years ago

The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea

a_sh-v [17]

Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}$

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

$\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60$

7 0

3 years ago

Read 2 more answers

Upon descent, an airplane is 20,000 feet above the ground. The air traffic control tower is 200 feet tall. It is determined that

PIT_PIT [208]

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

6 0

3 years ago