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Andre45 [30]
4 years ago
14

Find the common ratio for the following sequence. 64, 16, 4, 1, ...

Mathematics
2 answers:
insens350 [35]4 years ago
8 0
Common ratio = a2 / a1 or a3/a2
= 16/64 = 1/4

In short, Your Answer would be 1/4

Hope this helps!
Blababa [14]4 years ago
4 0
The answer is 1/4
hope this helped
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Solve for x and y
bekas [8.4K]

Answer:

x = 2√2

y = 2√6

Step-by-step explanation:

Consider the ratio of the two legs of the two smaller interior right triangles. (refer to attached diagrams for the triangles - I have outlined one in blue and the other in red)

These will be equal since the triangles are similar

shorter leg : longer leg

(blue triangle = red triangle)

⇒ x : 4 = 2 : x

⇒ x/4 = 2/x

⇒ x² = 8

⇒ x = √8

⇒ x = 2√2

Now we have x, we have the two legs of the right triangle with hypotenuse labelled y.

Using Pythagoras' Theorem a² + b² = c² (where a and b are the legs and c is the hypotenuse)

⇒ 4² + (2√2)² = y²

⇒ y² = 24

⇒ y = √24

⇒ y = 2√6

7 0
2 years ago
In a bag of jellybeans there are 6 purple jellybeans, 5 blue jellybeans, 3 yellow jellybeans, 2 green jellybeans, and 4 red jell
ikadub [295]

Answer:

9/10

Step-by-step explanation:

There are 20 and 2 green 20-2 is 18 so 18/20 simplified is also 9/10

7 0
3 years ago
Read 2 more answers
Ow to do this please help I’m 10in six grade I skip don’t no why but please help
ohaa [14]
To do this, you can just multiply across. 3 times 1 equals 3 so your numerator is 3. 2 times 4 equals 8. Then, your answer would be 3/8. Hope this helps :)
4 0
3 years ago
Read 2 more answers
Solve for the missing side. Round to the nearest tenth.
muminat

Answer:

? = 7.2

Step-by-step explanation:

Remark

Is that a misshapen circle or is it an ellipse? I'm going to assume it is a circle, but if I am wrong, leave a comment. A tangent will meet a diameter's end at right angles which allows you to use the Pythagorean theorem.

Formula

a^2 + b^2 = c^2

Givens

c = 12

a = 9.6

b = ?

Solution

c^2 - a^2 = b^2

144 - 92.16 = b^2

b^2 = 51.84                          Take the square root of both sides

sqrt(b^2) = sqrt(51.84)

b = 7.2

6 0
3 years ago
Find the sum of: 72 − 104 + 5 and -32 + 4 - 10. What should be added to 32 + 32 + 3 to get 3 + 3 ? (1 mark) 3. Subtract the sum
Rzqust [24]

Answer:

a). -65

b). -61

c). -20ab + 3bc +3ac

Step-by-step explanation:

According To the Question,

a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .

  • (72 − 104 + 5) + (-32 + 4 - 10)
  • (-27) + (-38)
  • -27 - 38
  • -65

b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .

  • Thus,  (32 + 32 + 3) + X = 3 + 3
  • 67 + X = 6
  • X = 6 - 67
  • X = -61

c). Subtract  the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.

  • Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
  • (ab + 5bc - ac) - (21ab + 2bc - 4ac)
  • ab + 5bc - ac - 21ab - 2bc + 4ac
  • -20ab + 3bc + 3ac

5 0
3 years ago
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