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Sladkaya [172]
4 years ago
11

Jack buys 4/3 pounds of plums. Martin buys 6/3 pounds of apples. Who buys more fruit? Explain your answer.

Mathematics
2 answers:
Sunny_sXe [5.5K]4 years ago
8 0
They both have the same denominator or bottom half of the fraction so you need to compare the numerators. 6 is more than 4 so Martin bought more fruit than Jack.  Hope this helps. 
navik [9.2K]4 years ago
8 0
Martin buys more fruit because he buys 6/3, and 6 is greater than 4, and Jack buys 4/3, so Martin bought more food than Jack. There's a difference of 2/3 between what Jack and Martin brought.
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Answer:

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Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

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