All categories

3 years ago

Jack buys 4/3 pounds of plums. Martin buys 6/3 pounds of apples. Who buys more fruit? Explain your answer.

2 answers:

8 0

They both have the same denominator or bottom half of the fraction so you need to compare the numerators. 6 is more than 4 so Martin bought more fruit than Jack. Hope this helps.

navik [9.2K]3 years ago

8 0

Martin buys more fruit because he buys 6/3, and 6 is greater than 4, and Jack buys 4/3, so Martin bought more food than Jack. There's a difference of 2/3 between what Jack and Martin brought.

You might be interested in

I need help plzzzzzzzzzzzzzzzzzzzzz

blagie [28]

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

106/2 = x

53 = x

4th box

180=102+2x

180-102=2x

78/2 = x

39 = x

4th box

180 = 73+81 +x

180-73-81=x

26 = x

5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

180=62-2x

180-62=2x

118=2x

118/2=x

59 = x

7th box

180 = 2*68 + x

180-2*68=x

44 = x

3 0

2 years ago

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

3 years ago

Find the value of y for which line a is parallel to line b.

alexdok [17]

Y+38°= 180 beacuse if a and b are parallel they are co interior angles. This means that they will at to 180.

y=180-38= 142°

Answer: 142°

Drew out some hopefully helpful pictures below. Hope they help! let me know if you still have any questions!

6 0

3 years ago

Math problem.................................................................. Nah fam you ain't gonna answer it correctly also

diamong [38]

Answer:

Step-by-step explanation:

8 0

3 years ago

How many pairs of whole numbers have sum of 110

alisha [4.7K]

Because the number is even, then the number of possible combinations will be: 110/2 = 55 let's consider a simpler example, the number: 10, then we have: 10+0, 9+1, 8+2, 7+3, 6+4, which is equal to 10/2 =5 combinations. Note: We are not considering permutations between the elements of the sum therefore 10+0, 0+10 counts as one combination.

7 0

3 years ago

Read 2 more answers