Question

Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and​ 4, for which ​f(-​2)=-18.

Answer 1

Answer:

Step-by-step explanation:

hello :

f(x) = a(x+3)(x+1)(x-4)

now calculate a  if f(-2)=18   means when x=-2   y=18

so : a(-2+3)(-2+1)(-2-4)=18

6a=18

a=18/6=3

conclusion : f(x) = 3(x+3)(x+1)(x-4)