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morpeh [17]
3 years ago
13

Draw a structural formula for an alkyne of molecular formula c8h14 that yields 3-ethylhexane on catalytic hydrogenation. click t

he "draw structure" button to launch the drawing utility.

Chemistry
2 answers:
saveliy_v [14]3 years ago
6 0

Answer:

3-ethyl-1-hexyne or 4-ethyl-1-hexyne.

Explanation:

Hello,

By means of the more likely reagents to undergo the stated hydrogentation via catalysis with palladium or platinum, its structure is shown on the attached picture which is eligible for either 3-ethyl-1-hexyne or 4-ethyl-1-hexyne since they lead to the very same product. Do not forget that such hydrogenation covers up all the insaturations turning out into the specified alkane.

Best regards.

OverLord2011 [107]3 years ago
3 0

If it an alkyne and gives 3-ethylhexane  on hydrogenation then the reaction will be

There will be three isomers of alkyne with given molecular formula

The reactions are shown in the attached figure


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What is the resultant molarity of 20mL of a 3.5M solution is diluted to 100mL? Will mark brainliest
motikmotik

Answer:

The resultant molarity is 0,7 M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

3,5 M x 20 ml= C2 x 100ml

C2= (3,5 M x 20 ml)/100ml

<em>C2= 0,7M</em>

4 0
3 years ago
A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/
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Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

<u>2.67%</u>

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

<u><em>You are calculating </em></u><u><em>weight /Volume</em></u><u><em> not weight/weight % or percent by mass of the solute</em></u>

Here the <u>weight/weight % or percent by mass</u> of the solute is asked : So first convert the<u> VOLUME OF SOLUTION into MASS</u>

Density of potassium nitrate in water KNO3 = 2.11 g/mL

density=\frac{mass}{volume}

Density = 2.11 g/mL

Volume of solution = 86.4 mL

2.11=\frac{mass}{86.4}

mass = 2.11\times 86.4

mass=182.3grams

Mass of Solute = 4.87 g

Mass of Solution = 183.2 g

w/w% of the solute =

= \frac{mass\ of\ solute}{mass\ of\ solution}\times 100

=\frac{4.87}{183.2}\times 100

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Calculate the second volumes. <br> 7.03 Liters at 31 C and 111 Torr to STP
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The second volume :    V₂= 0.922 L

<h3> Further explanation </h3><h3>Given </h3>

7.03 Liters at 31 C and 111 Torr

Required

The second volume

Solution

T₁ = 31 + 273 = 304 K

P₁ = 111 torr = 0,146 atm

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At STP :  

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Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

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