Answer:
See below
Step-by-step explanation:
You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.
However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.
The process is
NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)
The rates of the forward and reverse processes are equal, so you see no net change.
Answer:
Characteristics. They are all relatively inert, corrosion-resistant metals. Copper and gold are colored. These elements have low electrical resistivity so they are used for wiring.
Explanation:
Hope this help u
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<u>Al2(SO4)3</u>
<u>Option: E</u>
<u>Explanation:</u>
The freezing point lowering of a solution depends on the number of ions and molecules that dissolve in water solution. So when there are more number of molecules, the freezing point will also be reduced more.
Now let us look at Al2(SO4)3. Here, it produces a total of 5 molecules. i.e (2 Al(3+) and 3 SO4(2-)). If we take the other choices from first:
MgBr2 - It produces a total of 3 molecules. (1 Mg(2+) and 2 Br(-))
HOCH2CH3 - This produces 1 molecule as it remains the same as HOCH2CH3 because it is covalent and does not dissociate in water.
NaNO3 - This produces 2 molecules. (1 Na(1+) and 1 NO3(-))
C6H12O6 - This also produces 1 molecule same as HOCH2CH3 because it is also covalent and does not dissociate in water.
Na3PO4 - This produces a total of 4 molecules. (3 Na(+) and 1 PO4(3-))
Thus, from the above analysis, it shows that Al2(SO4)3 has more molecules compared to others. When there are more molecules, the freezing point is also lower.
Answer:
Explanation:
Each magnesium atom loses two electrons and each iodine atom gains one electron. So there should be a 1-to-2 ratio of magnesium ions to iodide ions.