Best Answer: <span>(a)
8.9 x 10^-7 = x^2 / 0.15-x
x = [OH-] = 0.00037 M
pOH = 3.4
pH = 14 - 3.4 = 10.6
(b)
Ka = Kw/Kb = 5.6 x 10^-10 = x^2 / 0.20-x
x = [H+] = 0.000011 M
pH = 5.0</span>
Answer:
O2
Explanation:
for find the limiting reactant you must calculate the moles of the reactants from the amount that you have and from the MM:
MM FeS2 = 120n = 26.2g / 120g/mol = 0,218 mol
MM O2 = 32n = 5,44g/32g/mol = 0,17 mol
The limiting reactant is
O2
Answer:
In graphite, each carbon atom is covalently bonded to 3 other carbon atoms. ... These extra electrons are delocalised, or free to move, in the area between layers of carbon atoms. As these electrons are free to move they are able to carry charge and thus graphite can conduct electricity.
Explanation:
Explanation:
A period 4 element is one of the chemical elements in the fourth row (or period) of the periodic table of the elements.
...
Period 4 element.
Hydrogen Rubidium
Strontium
Yttrium
Zirconium
Niobium
Answer:
1.17 grams
Explanation:
Let's consider the balanced equation for the combustion of ethylene.
C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(l)
We can establish the following relations:
- 1411 kJ are released (-1411 kJ) when 1 mole of C₂H₄ burns.
- The molar mass of C₂H₄ is 28.05 g/mol.
The grams of C₂H₄ burned to give 59.0 kJ of heat (q = -59.0 kJ) is:
