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Alex Ar [27]
3 years ago
13

Write a balanced nuclear equation for the beta decay of protactinium

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
7 0
_{91}^{231}Pa --\ \textgreater \  _{92}^{231}U + _{-1}^{0}e
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Explanation:

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What is thermodynamics ??? <br>don't explain .-. !!!​
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Considering all types of aerosols, what is their net effect on the climate system:
timurjin [86]
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6 0
3 years ago
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A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
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A 4.10 −g sample of a mixture of CaO and BaO is placed in a 1.00-L vessel containing CO2 gas at a pressure of 735 torr and a tem
insens350 [35]

Answer:

The mass % of CaO is 9.37%%

Explanation:

<u>Step 1: </u>Data given

Mass of the mixture = 4.10 grams

Volume of the vessel = 1.00 L

The vessel contains CO2 with a pressure of 735 torr and temperature = 26 °C

The pressure of the remaining CO2 is 155 torr

<u>Step 2:</u> The balanced equation

CaO/BaO + CO2 → CaCO3 /BaCO3

.

<u>Step 3</u>: Calculate moles CO2 (via ideal gas law)

CO2 is the only gas, this means the drop in the pressure is caused by CO2

Δp = 735 torr - 155 torr = 580 torr

580 torr = 0.763 atm

n = PV/RT = (0.763atm)(1.00L) / (0.08206 L*atm/K*mol)(299) = 0.0391 moles CO2 initial

moles reacted = 0.0311 moles CO2

Step 4: Calculate mass of CaO and BaO

Let's suppose  x = mass of CaO. Then mass of BaO = 4.10-x.

In the balanced equation, we notice the mole ratio of CaO/BaO with CO2 is 1:1. This means the number of moles CaO + moles BaO = Number of moles CO2

moles CaO + moles BaO = moles CO2

x/56.08 + (4.10-x)/153.33 = 0.0311

56.08 (x/56.08 + (4.10-x)/153.33) = (56.08)(0.0311)

x + (0.366)(4.10-x) = 1.744

x + 1.5006 - 0.366x = 1.744

0.634x = 0.2434

x = 0.384g CaO

4.1-x = g BaO = 3.716 grams

%CaO = (0.384 g / 4.10 g) x 100 = 9.366% ≈ 9.37

The mass % of CaO is 9.37%

7 0
4 years ago
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