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Annette [7]
3 years ago
7

Darren drives to school in rush hour traffic and averages 30 mph. He returns home in mid-afternoon when there is less traffic an

d averages 40 mph. What is the distance between his home and school if the total traveling time is 1 hr 45 min?
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0

Answer:

Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time.

The formula for distance problems is: distance = rate × time or d = r × t.

Things to watch out for:

Make sure that you change the units when necessary. For example, if the rate is given in miles per hour and the time is given in minutes then change the units appropriately.

It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.

Step-by-step explanation:

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Which is log x+ 6 log(x+7) written as a single logarithm.
Elina [12.6K]

Answer: option d.

Step-by-step explanation:

 To solve this problem you must keep on mind the properties of logarithms:

log(b)-log(a)=log(\frac{b}{a})\\\\log(b)+log(a)=log(ba)\\\\a*log(b)=log(b)^a

Therefore, knowing the properties, you can write the expression gven in the problem as shown below:

5logx+6log(x+7)=logx^5+log(x+7)^6=logx^5(x+7)^6

Then, the answer is the option d.

4 0
3 years ago
Read 2 more answers
Graph this quadratic funtion f(x)=x^2+1
lawyer [7]
Let's examine the given function first:
f(x) = x^2 + 1    is the same as    f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept:  f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)

Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1.  So:  Graph y=x^2.  Then translate the whole graph UP by 1 unit.  That's it.  Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
6 0
3 years ago
The cost of 12 oranges and 7 coples is 55.36. Eight oranges and apples cost $3.68. Find the cost
victus00 [196]

Hello there i hope you are having a good day :) Your question : The cost of 12 oranges and 7 couples is 55.36. Eight oranges and apples cost $3.68. Find the cost  of each : Firstly you would do oranges = O Apples = A. Then 12 oranges + 7 apples = 5.36 12o + 7A = 5.36 then you would take away from both sides so -12o Take away -12o = 7o = 5.36 - 12A now you would divide this by 7 so 7 cancels each out so you are left with 5.36/ 7 = 0.76 Then it would equal 0.76 - 12o/7 This would equal the amount of apples to be $0.76 each now for the oranges you would do the same that you work out for the apples.

Hopefully that help ya :)

4 0
3 years ago
Stella works for a company that makes aluminum cans. A large soup can have a radius of 8 centimeters and a height of 20 centimet
4vir4ik [10]
Could possibly be 36
6 0
3 years ago
Pls help!!! Quiz!!! please
melomori [17]

Answer:

It's 27 ,Hope I helped!!! Good luck on you quiz too!!!

Step-by-step explanation:

8 0
3 years ago
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