Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
I don’t see any question. What is the question.
Step-by-step explanation:
23. area of rect,r = 11 x 3.5 = 38.5cmsq
area of tri, t = 6 x3.5/2 = 10.5 cmsq
area of shaded region, sr = r-t
=> sr = 38.5- 10.5 = 28.5cmsq
24. area of square, s = 10x10 = 100mmsq
area of circle, c = pi x 5^2 = 78.5mmsq
area of shaded region, sr = s - c
=> sr = 100- 78.5 = 22.5mmsq
25. area of circle, c = pi x 6^2 = 113.04insq
area of tri, t = 6x12/2 = 36insq
area of shaded region, sr = c - t
=> sr = 113.04 - 36 = 77.04insq
Answer:
-5x+22
Step-by-step explanation:
we are simplifying
2x-(-8)-7x+4+10=
2x+8+-7+4+10=
2x+8+-7x+4+10
(2x+-7)+(8+4+10)= -5x+22
Hope it helps
