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emmasim [6.3K]
3 years ago
7

Determine the greatest common divisor of the elements of the set \[ s = \{ n^{13} - n \mid n \in \mathbb{z} \}. \]

Mathematics
1 answer:
Kay [80]3 years ago
5 0

Answer:

2730

Step-by-step explanation:

We want to determine the greatest common divisor of the elements of the set  S = \{ n^{13} - n \mid n \in \mathbb{Z} \}.

We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.

Now, n^{13} \equiv n \mod p if p-1 divides 12.

Since the  of 12 are 1,2,3,4, 6, 12, the corresponding primes are 2, 3, 5, 7, 13.

Therefore, the gcd of the elements in 2^{13}-2 and 3^{13}-3$ is 2 \cdot 3 \cdot 5 \cdot 7 \cdot 13.

2*3*5*7*13=2730

Therefore, the gcd of the elements in set S is 2730.

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