Answer:
Step-by-step explanation:
9) (25-x^2 )(a+2) = (5-x)(5+x)(a+2)
11) 9(v-3)+u^2(3-v)
9(v-3)+u^2( -v+3)
9(v-3)-u^2( v-3)
(9-u^2)(v-3)
(3-u)(3+u)(v-3)
1/8, 7/2, 5/6, 10/3
just swap numerator and denominator for each
To find the vector representation between the points (5,5) and (-3,-2), we need to find the difference in the x and y components. To do this we just need to do (-3-5) and (-2-5) this gives us an i component of -8 and a j component of -7
Final answer:
v=-8i-7j
Hope I helped :)
And PS, eventually you will get to three dimensions which uses i j and k ;)
The equation of a line can be written in the form y=mx+b, where m is the slope and b is the y-intercept.
Since you are looking for a line with a slope (m) of -3/4 and a y-intercept (b) of 5... the equation you want is y = -3/4 x + 5
If x=mx-3 (which is not clear from your input),
3
then x-mx = -3, or mx-1x = 3, and x(m-1) = 3, and so x = ---------
m-1