Answer:
The final velocity of the car after the acceleration takes place is 13 m/s.
Explanation:
The final velocity can be calculated using the following equation:
Where:
: is the initial velocity = 0 (starts from rest)
a: is the acceleration = 2 m/s²
t: is the time = 6.5 s
Hence, the final velocity is:
Therefore, the final velocity of the car after the acceleration takes place is 13 m/s.
I hope it helps you!
A.brass is heavier than water.
Answer:
9.4 m
Explanation:
We can use a moving frame of reference with the same speed as the car. From this frame of reference the car doesn't move. The origin is at the back of the car, the positive X axis points back and the positive Y axis points up.
If the ballon is launched at 9.7 m/s at 39 degrees of elevation.
Vx0 = 9.7 * cos(39) = 7.5 m/s
Vy0 = 9.7 * sin(39) = 6.1 m/s
If we ignore air drag, the baloon will be subject only to the acceleration of gravity. We can use the equation of position under constant acceleration.
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 = 0
a = -9.81 m/s^2
It will fall when Y(t) = 0
0 = 6.1 * t - 4.9 * t^2
0 = t * (6.1 - 4.9 * t)
t1 = 0 (this is when the balloon was launched)
0 = 6.1 - 4.9 * t2
4.9 * t2 = 6.1
t2 = 6.1 / 4.9 = 1.25 s
The distance from the car will be the horizonta distance it travelled in that time
X(t) = X0 + Vx0 * t
X(1.25) = 7.5 * 1.25 = 9.4 m
90 J / 2.2 s = 41 W. 41 Watts is the power <span>required to give a brick 90 J of potential energy in a time of 2.2 s</span>
Answer:
Frequency, 
Explanation:
Given that,
Wavelength of the light,
We need to find the frequency of light. We know that light is an electromagnetic wave. It moves with the speed of light. So,
f is the frequency of light
So, the frequency of light is 
. Hence, this is the required solution.
