Question

Two protons in a molecule are 3.70 10-10 m apart. Find the electric force exerted by one proton on the other. magnitude

Answer 1

Answer:

1.68 × 10⁻⁹ N

Explanation:

We can find the magnitude of the electric force (F) using the Coulomb's law.

$F=k\frac{q_{1}q_{2}}{r^{2} }$

where,

k: Coulomb's constant

q: charges

r: distance

The charge of a proton is 1.60 × 10⁻¹⁹ c.

$F=8.99 \times 10^{9} N.m^{2} .C^{-2} .\frac{(1.60 \times 10^{-19}C)^{2} }{(3.70 \times 10^{-10}m)^{2} } =1.68 \times 10^{-9}N$