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Vlad [161]
3 years ago
9

Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessne

ss and when they would have sensations of weightiness. In your discussion, talk about accelerations and forces. Then finish off your conclusion by using Newton's second law to explain why such accelerations and force conditions cause these sensations.
Physics
1 answer:
masya89 [10]3 years ago
3 0

Answer:

he lower part of the curve     N = M (g + v² / r)

upper part of the curve          N = m (v² /r -g)

Explanation:

In a roller coaster there is a long climb that allows the car to acquire gravitational potential energy, when this energy is converted into kinetic energy, there is a raven, in these curves we have two parts the lower part, where you have a feeling of great weight and another in the upper part where you have a feeling of weightlessness.

These sensations can be explained using Newton's second law, let's apply it to the lower part of the curve

         N-W = m a

acceleration is centripetal

        a = v² / r

we substitute

        N = mg + m v² / r

        N = M (g + v² / r)

In this part the apparent weight is increased by the speed of the body squared, it feels like a lot of fart.

In the upper part of the curve the force of gravity continues to act downwards, the normal that is the reaction of the surface also goes downwards, the centripetal acceleration pointing towards the center of the curve has a vertical downward direction

        -N -W = -m a

         N = ma -W

         N = m (v² / r -g)

In this case we see that the normal that gives the sensation decreases, which is why we feel a loss of weight, in the case of v2 / r = g, the request is total and the sensation of weightlessness.

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Inga [223]

Significa que en su investigación, debe proporcionar suficiente información para que otras personas que lean su investigación puedan hacer la investigación nuevamente.

4 0
4 years ago
Which trait shared by dolphins and bats possibly lead to the evolution of echolocation in these two animal groups? the need to m
Lisa [10]

A trait shared by dolphins and bats that possibly led to the evolution of echolocation in these two animal groups will be the need to move quickly through dark environments.

<h3>What is the evolution of echolocation?</h3>

Our understanding of the evolution of echolocation in bats has shifted as a result of recent molecular phylogenies. These phylogenies imply that bats with advanced echolocation

According to one interpretation of these trees, laryngeal echolocation originated in the ancestor of all living bats. Echolocation may have been lost in Old World fruit bats

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A trait shared by dolphins and bats that possibly led to the evolution of echolocation in these two animal groups will be the need to move quickly through dark environments.

Hence option A is correct.

To learn more about the evolution of echolocation refer to the link;

brainly.com/question/20789287

3 0
2 years ago
1. A fish swims 340 feet. Is this a distance or a<br> displacement?
In-s [12.5K]
This is a distance not a displacement
3 0
3 years ago
An object is moving with constant non-zero velocity. Which of thw following statements about it must be true
hram777 [196]

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

5 0
3 years ago
Suppose you increase your walking speed from 4 m/s to 15 m/s in a period of 1 s. What is your acceleration?
hichkok12 [17]

Answer:

The acceleration is: 11\,\frac{m}{s^2}

Explanation:

Recall that acceleration is defined as the change of velocity over the time it took to produce this change. This is expressed mathematically as:

a=\frac{v_f-v_i}{t_f-t_i}

with v_i being the initial velocity of the person (in our case 4 m/s);

v_f being his final velocity (in our case 15 m/s);  

and the difference t_f-t_i the time the change in velocity took (in our case 1 second).

Therefore in our example, the person's acceleration is:  

a=\frac{v_f-v_i}{t_f-t_i}\\a=\frac{15-4}{1}\,\frac{m}{s^2} \\a=11\,\frac{m}{s^2}

7 0
3 years ago
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