Help!! Would the answer be c??

Solve for a and b<br> (6a-3)=(7b-10)

Free_Kalibri [48]

Answer:

for A= $\frac{7b-7}{6}$ and for B= $\frac{6a+7}{7}$

Step-by-step explanation:

For A

$\left(6a-3\right)=\left(7b-10\right)$

$6a-3+3=7b-10+3$

$6a=7b-7$

$\frac{6a}{6}=\frac{7b}{6}-\frac{7}{6}$

$a=\frac{7b-7}{6}$

For B

$\left(6a-3\right)=\left(7b-10\right)$

$7b-10=\left(6a-3\right)$

$7b-10=6a-3$

$7b-10+10=6a-3+10$

$7b=6a+7$

$\frac{7b}{7}=\frac{6a}{7}+\frac{7}{7}$

$b=\frac{6a+7}{7}$

3 0

2 years ago

The tangent line to y= f(x) at (4,-6) passes through the point (10,9) Compute the following, f(4) and f'(4)

Anni [7]

The solution to your problem is as follows:

The tangent line passes through (4,-6), so x = 4 when y = -6

=> f(4) = -6

The tangent line will have a constant gradient.

gradient is m = (-6 - 9)/(4 - 10) => 5/2

Equation is y - 9 = (5/2)(x - 10)

=> y - 9 = (5/2)(x-10)

<span>i.e. y = (5/2)(x-10) + 9
</span> y = (5/2)x - 25 + 9 = y = (5/2)x - 16

Now, f '(x) = dy/dx = 5/2

so, f '(4) = 5/2....i.e. gradient is 5/2 whatever the value of x.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

3 0

2 years ago

Look at the following numbers:

Elodia [21]

C. hope this helps :)

5 0

2 years ago

Read 2 more answers

3(x - 2) + 2 = 5(x - 3) + 9 por fa

hram777 [196]

Answer:

x = 1

Step-by-step explanation:

Given

3(x - 2) + 2 = 5(x - 3) + 9 ← distribute and simplify both sides

3x - 6 + 2 = 5x - 15 + 9

3x - 4 = 5x - 6 ( subtract 5x from both sides )

- 2x - 4 = - 6 ( add 4 to both sides )

- 2x = - 2 ( divide both sides by - 2 )

x = 1

5 0

3 years ago

Which two numbers doesStartRoot 128 EndRoot lie between on a number line? 11. 0 and 11. 1 11. 2 and 11. 3 11. 3 and 11. 4 11. 4

Alex73 [517]

A number line is a representation of a graded straight line. The number √128 will lie between 11.3 and 11.4.

<h3>What is a number line?</h3>

A number line is a representation of a graded straight line that serves as an abstraction for real numbers, which are represented by the letter R. A real number is considered to correspond to every point on a number line, and a point to every real number.

In order to know the location of the √128, we need to write the number √128 in decimal form, therefore, the value of √128 can be written as,

$\sqrt{128} = 11.3137 \approx 11.31$

Now, on the number line if we plot √128 we will see that it will lie between 11.3 and 11.4, as shown below.

Hence, the number √128 will lie between 11.3 and 11.4.

Learn more about Number Line:

brainly.com/question/557284

7 0

1 year ago