Question

A bouquet of lilies and tulips has 20 flowers. Lilies cost 3$ each and tulip cost 2$ each. The bouquet costs $48 how many lilies x and tulips y are in a bouquet? Show how you got your equations and answers.

Answer 1

Answer:

8 lilies and 12 tulips flowers

Step-by-step explanation:

Let x be the lilies and y be the tulips flower.

Given:

Total flowers = 20

Lilies cost = $3

Tulip cost = $2

Bouquet cost = $48

Solution:

A bouquet of lilies and tulips has 20 flowers, so sum of the lilies and tulip flower is equal to 20 flower,

$x+y =20$ -----------------(1)

Since lilies cost $3 each, tulip cost $2 each and bouquet cost is equal to $48, so we write the equation as.

$3x+2y=48$ ------------------(2)

From equation 1.

$x=20-y$ --------------(3)

Substitute $x=20-y$ in equation 2 and simplify.

$3(20-y)+2y=48$

$60-3y+2y=48$

$60-y=48$

$y=60-48$

$y=12$

Substitute $y=12$ in equation 3.

$x = 20-12$

$x=8$

Therefore, 8 lilies and 12 tulips flowers in the bouquet.