Which statement is best represented by the inequality c greater-than 3 and one-half?

Mathematics

2 answers:

romanna [79]3 years ago

5 0

Answer:

The anwser for this problem is b or Chef Andre used more then 3 1/2 cups of flour

Step-by-step explanation:

Took this test in edge. Hope this helps!

luda_lava [24]3 years ago

3 0

Answer: Chef Andre used more than 3 and one-half cups of flour.

Step-by-step explanation:

This is the > ‘greater than sign. For the question, we are to get the inequality that shows that"c is greater-than 3 and one-half".

Let Chef Andre be represented by c. Greater than is used to denote a situation when something is."more than" another thing. In this scenario,

Chef Andre used more than 3 and one-half cups of flour. This can be represented as C > 3 1/2.

This is the correct answer.

You might be interested in

What is the product of −2 1/4 and 2 1/2?

Alexeev081 [22]

Answer:

-5 5/8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is p

Vedmedyk [2.9K]

I like the 'question mark' at the end:

26 letters (English), 10 digits (0,1,...9)

26*26*10*10*10 = 676000

Now, this was for LLDDD (Letter Letter Digit Digit Digit)

It seems this is the order they want. Other wise, one should multiply by all the combinations in the order: LDLDD, DLLDD, etc ... (10 combinations), but again it seems they want this LLDDD

So 676000

5 0

3 years ago

I dont understand these problems |×| - 1 < 5 , 3x + 4 <-2, 5x/7 -2=1, 9(2x+3)=10

Marta_Voda [28]

$|x|-1$

3 0

4 years ago

Evaluate lim x→∞ (3x+1)^(4/x), using l'hospital's rule as needed. show all work using proper notation. as you show your work, if

Alborosie

$\displaystyle\lim_{x\to\inty}(3x+1)^{4/x}=\lim_{x\to\infty}e^{\ln(3x+1)^{4/x}}=e^{\lim\limits_{x\to\infty}\ln(3x+1)^{4/x}}$

$\displaystyle\lim_{x\to\infty}\ln(3x+1)^{4/x}=\lim_{x\to\infty}\frac{4\ln(3x+1)}x\stackrel{\mathrm{LHR}}=\lim_{x\to\infty}\frac{4\frac3{3x+1}}1=\lim_{x\to\infty}\frac{12}{3x+1}=0$

$\implies\displaystyle\lim_{x\to\infty}(3x+1)^{4/x}=e^0=1$

4 0

3 years ago

Write an equation where the left side is your power of 10 times n and the right side is the result of multiplying 0.1515... by t

Neko [114]

Answer:

$n10^x = 0.1515x$