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Gnom [1K]
3 years ago
12

For two days ,Leo counted the number of Canadian geese in the park He counted 3 times as many geese on the first day as he did o

n the second day How many Canadian geese died d he count the first day
Mathematics
1 answer:
Bogdan [553]3 years ago
8 0
There is not enough information to answer this question.
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What postulate or theorem can be used to prove that ΔEFG ≅ ΔJHG?
OlgaM077 [116]
The answer Is C: SAS Congruence Postulate.
6 0
3 years ago
Sally Reynolds sells real estate along the coastal area of Northern California. Below are her total annual commissions between 2
tatiyna

Answer:

Mean = $229.32

Median = $231.15

Mode = $268.4

Step-by-step explanation:

Mean = the average.

The average is the sum of variables divided by the number of variables.

x = each variable

N = number of variables = 11

Average = (Σx)/N = (236.09 + 204.43 + 253.82 + 268.4 + 231.15 + 205.7 + 262.18 + 162.77 + 268.4 + 224.45 + 205.17)/11

Mean = 2522.56/11 = $229.32

b) Median is the value that falls at the middle of the data set if all the variables are arranged in ascending or descending order.

So, to find the Median, we first arrange the variables in ascending order.

162.77

204.43

205.17

205.70

224.45

231.15

236.09

253.82

262.18

268.4

268.4

Since there are 11 variables, the Median is the number that falls at the middle of the distribution, that is, at the sixth position.

Median = $231.15

c) Mode is the number that appears the most in a distribution.

In this distribution, only 268.4 appears more than once.

Hence, the more is $268.4

8 0
3 years ago
The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,
ivanzaharov [21]

Answer:

  CD = 14 cm; DE = 21 cm

Step-by-step explanation:

The perimeter is the sum of side lengths (in centimeters), so ...

  CD + DE + CF + EF = 55

  CD + DE + 8 + 12 = 55 . . . . . . . substittute for CF and EF

  CD + DE = 35 . . . . . . . . . . . . . . subtract 20

___

The segment DF is a diagonal of the rhombus, so bisects angle D. That angle bisector divides ΔCDE into segments that are proportional. That is, ...

  CD/DE = CF/EF = 8/12 = 2/3

___

So, we have two segments whose sum is 35 (cm) and whose ratio is 2 : 3. The total of "ratio units is 2+3=5, so each must stand for a length unit of 35/5 = 7 (cm). The sides are ...

  CD = 2·7 cm = 14 cm

  DE = 3·7 cm = 21 cm

<em>Check</em>

  CD + DE = (14 +21) cm = 35 cm . . . . . matches requirements

7 0
4 years ago
Can someone please help me answer this question, and please help me how you arrived to your correct answer? thank you!
galben [10]
\sqrt{ - 180 {x}^{16} } \\ = \sqrt{( - 1) \times \: 2 \times 2 \times 3 \times 3 \times 5 \times {x}^{8} \times {x}^{8} } \\ = (2 \times 3 \times {x}^{8} ) \sqrt{( - 1) \times 5 } \\ = 6 {x}^{8} \times \sqrt{ - 1} \times \sqrt{5} \\ = 6 {x}^{8} i \: \sqrt{5}

so answer is option 4
3 0
3 years ago
What is the area of sector​ GPH? the angle inside the circle measures 80º and the radius from p to h is 15
faltersainse [42]
Area = π r²

area of the required sector = (80/360) π * 15²
                                           ≈ 157.08
6 0
3 years ago
Read 2 more answers
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