Question

If two ppl working at 7.00 per hour work 8 hours making trays that cost 35.00 each if it cost 14.00 to make the trays how many would they have to make to cover the cost including labour

Answer 1

Answer:

They have to make 6 trays to cover the cost including labor.

Step-by-step explanation:

Given:

Number of labor =2

Cost per hour of labor =7.00

Number of hours they work = 8

Selling cost of each trays =35.00

making cost of each tray = 14.00

We need to find the number of trays they to make to cover the cost including the labor.

Solution:

Let the number of trays be 'x'.

First we will will find the Total cost of labor.

Total cost of labor is equal to Number of labor multiplied by Cost per hour of labor multiplied by Number of hours they work.

framing in equation form we get;

Total cost of labor  = $2\times 7\times8 =112.00$

Now we can say that;

Selling price of each tray multiplied number of trays equal to Making cost of each trays multiplied by number of tray plus Cost of labor.

framing in equation form we get;

$112+14x=35x$

Combining like terms we get;

$112= 35x-14x\\\\112=21x$

Dividing both side by 21 using division property of equality we get;

$\frac{112}{21} = \frac{21x}{21}\\\\5.33=x$

Hence They have to make 6 trays to cover the cost including labor.