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3 years ago

Step-by-step explanation please (Worth 3 marks)

Mathematics

2 answers:

atroni [7]3 years ago

5 0

Answer:

62°

Step-by-step explanation:

180-118=62

62+62=124

180-124=56

118-56=62

stepan [7]3 years ago

5 0

Answer:

<YQP + <YQR =180 degrees [Sum of angles in straight line is 180 degrees]

or, <YQP +118 =180

or, <YQP =62=<YPQ [Base angles of isosceles triangle are equal]

or, <YPQ =a=62 [XY // PQ and alternate angles]

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How to solve cube roots

Rom4ik [11]

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3 years ago

Factor this expression completely, then place the factors in the proper location on the grid. a^3y + 1

ivolga24 [154]

Answer:

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

Step-by-step explanation:

We are to factorize the expression $a^{3y} + 1$ completely. To do this, we will apply the expression below;

The expression can be rewritten as $a^{3y} + 1^{3}$

To factorize the expression, we need to first factorize $(a^{y}+1 )^{3}$ first

$(a^{y}+1 )^{3} =(a^{y}+1 )(a^{y}+1 )^{2}\\= (a^{y}+1 )((a^y)^{2} } + 2a^{y} +1)\\= (a^y)^{3} +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y+1\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +2(a^y)^{2}+a^y+( a^y)^{2}+2a^y\\(a^{y}+1 )^{3} = ((a^y)^{3} + 1) +3(a^y)^{2}+3a^y\\$

The we will make $a^{3y} + 1^{3}$ the subject of the formula as shown;

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\(a^y)^{3} + 1^{3} = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$(a^y)^{3} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - (3(a^y)^{2}+3a^y)\\\\$

$a^{3y} + 1 = (a^{y}+1 )^{3} - 3a^y(a^{y}+1)\\\\$

This last result gives the expansion of the expression

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3 years ago

Solve -33 < 12x + 15 99.

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Approximately x=2.9.4

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3 years ago

Solve: 7.2 + 3.5

oksano4ka [1.4K]

Hello~

Here!

7 + 3.5

Ary~

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2 years ago

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Bogdan [553]

Answer:

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