Step-by-step explanation:
you would take how munch the price for one is and times it by 5
Answer:
43.531
Step-by-step explanation:
This problem needs the law of cosines since the three sides of the triangle are involved as well as one angle. The law of cosines is:
c^2 = a^2 + b^2 - 2ab*cos(C)
Where the lowercase letters are side values and capital letters are angle values. Just in case I will mention side a is the one with a length of 14, side b is 20 and c = 12.
Since it is asking for angle A instead of angle C we can rewrite the law of cosines to fit that, basically just rearranging the letters.
a^2 = c^2 + b^2 - 2cb*cos(A)
Now we just plug in and solve.
14^2 = 12^2 + 20^2 - 2*12*20*cos(A)
Rearrange to get A by itself
Now we take the inverse cosine, or arccos of both sides to get our answer.
Let me know if there is something in my explanation you don't understand.
The zeros of that expression are
- 1 + i√2
and
- 1 - i√2 .
For this we are going to use the equation f(x)=a|x+h|+k
Since there is no a shown, we know that a=1. This means the slope of the graph by 1's. (slope=1 one on the right side and slope=-1 on the left, because absolute value graphs are shaped like a "v".)
Since h=-2, just move the function to the left 2 units.
Since k=5, move the function up 5 units.
This basically means the vertex of the function is at the point (-2,5).
So put the point (-2,5) on your graph, then make the v-shape with a slope of 1 on the right side, and -1 on the left.
Sometimes if you aren't sure how the graph will look, just plug x-values into the function to get their corresponding y-values. Then see how the graph looks to check.
No, it cannot be used to create other regular inscribed polygons.
This plan only works with a hexagon. If you inscribe a square into a circle, the lengths of the sides will not be equal to the radius.