What is 456% as decimal

Mathematics

1 answer:

aleksandrvk [35]3 years ago

8 0

Answer:

4.56

Hope this helps. :)

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Vern has just opened a flower shop. Because of the startup costs, for the next month his net earnings for each bouquet are −$2.5

Basile [38]

Answer:

-$200

Step-by-step explanation:

Given that:

Net earning per bouquet for the month= - $2.50

On a particular day of the month, 20 bouquet was sold ;

Net earning for the day:

Net earning per bouquet * number of bouquet

-$2.50 * 80

= $200

Hence, net earning for Tuesday = - $200

6 0

3 years ago

Find f'(0.3) for f(x)= the integral from 0 to x of arccos(t)dt

Lady_Fox [76]

$\bf \textit{using the 2nd fundamental theorem of calculus}\\\\
\cfrac{dy}{dx}\displaystyle \left[ \int\limits_{0}^{x}\ cos^{-1}(t)dt \right]\implies cos^{-1}(x)
\\\\\\
f'(0.3)\iff cos^{-1}(0.3)\approx 1.26610367277949911126$

now.. 0.3 is just a value...we'e assuming Radians for the inverse cosine, so, if you check, make sure your calculator is in Radian mode

8 0

3 years ago

If one real number is equal to a second real number, and the second real number is equal to a third real number, then the first

svet-max [94.6K]

Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."

Step-by-step explanation: I think this is the problem ur on

8 0

2 years ago

A hotel claims that 8585% of its customers are very satisfied with its service. complete parts a through d below based on a ran

jek_recluse [69]

We can solve this problem using the binomial distribution. A binomial distribution<span> can be thought of as a success or failure outcome in an experiment or survey that is repeated multiple times.
</span>Probability function of binomial distribution has the following form:
$P= \frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}$
p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6.
We can now calculate the answer:
$P= \frac{6!}{5!(6-5)!} 0.85^5(1-0.85)^{6-5}=0.39$
The probability is 39%.
.

7 0

3 years ago

Kalen wrote 60:20 or 3:1 on his paper.what comparison statment would describe the ratios that he wrote?

shepuryov [24]

Answer:

3 teddy bears for each cookie he has.

6 0

3 years ago