5. Solve these recurrence relations together with the initial conditions given: a) aann = 5aann−1 − 6aann−2, nn ≥ 2 with aa0 = 0
aaaaaa aa1 = 1 b) aann = −4aann−1 − 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 1 c) aann = 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 4 d) aann = 2aann−1 + aann−2 − 2aann−3, nn ≥ 3 with aa0 = 3, aa1 = 6 aaaaaa aa2 = 0
1 answer:
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Answer:
The correct option is D.
Step-by-step explanation:
The given expression is
Difference of two squares property:
Using the above property, the given expression can be written as
Applying square we get
Therefore the correct option is D.