5. Solve these recurrence relations together with the initial conditions given: a) aann = 5aann−1 − 6aann−2, nn ≥ 2 with aa0 = 0
aaaaaa aa1 = 1 b) aann = −4aann−1 − 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 1 c) aann = 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 4 d) aann = 2aann−1 + aann−2 − 2aann−3, nn ≥ 3 with aa0 = 3, aa1 = 6 aaaaaa aa2 = 0
1 answer:
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Answer:
is the required decreasing order expression
Step-by-step explanation:
We have been given a polynomial:
The decreasing power means from highest power to the lowest power.
Highest power is 4 then 2 then 1 and then constant so, we will start from 4 an ends at constant.
is the required decreasing order expression.