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bixtya [17]
3 years ago
8

5. Solve these recurrence relations together with the initial conditions given: a) aann = 5aann−1 − 6aann−2, nn ≥ 2 with aa0 = 0

aaaaaa aa1 = 1 b) aann = −4aann−1 − 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 1 c) aann = 4aann−2, nn ≥ 2 with aa0 = 0 aaaaaa aa1 = 4 d) aann = 2aann−1 + aann−2 − 2aann−3, nn ≥ 3 with aa0 = 3, aa1 = 6 aaaaaa aa2 = 0

Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

Answer:

Step-by-step explanation:

Check attachment for solution

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Write the series 1-0.5-2+ ... for 12 terms using summation notation
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Answer:

The series

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<u><em>Step(i)</em></u>:-

Given series  1 -0.5 -2 +.........

we know that the sum of the sequence is called a series

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<u><em></em></u>

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