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2 years ago

Tyler has a lizard named Larry. Tyler wants to build a rectangular pen for Larry to run

Mathematics

1 answer:

QveST [7]2 years ago

7 0

Answer:

You can go for 1x9, 2x8, 3x7, 4x6, 5x5.

5x5 is the best as it builds a square, which maximizes space.

20*2.50 = $50.

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40 POINTS!!!!!!!! The length of a rectangle is 7 millimeters longer than its width. The perimeter is more than 62 millimeters.

Arte-miy333 [17]

a) L = W + 7

b) 2 ( L + W ) > 62

c) 2 ( W + 7 + W ) > 62

2w+14+2w>62

4w+14>62

4w > 48

w > 12

8 0

3 years ago

This my last one help

Lerok [7]

Answer:

A2 = 120

A3 = 60

A5 = 60

A6 = 120

Step-by-step explanation:

Angle 1 and 2 are supplementary, so A2 = 180 - 60, which is 120.

Angle 1 and 3 are vertical angles, which are always the same measure.

Angle 5 is alternate interior angles with 3, which means it is also 60.

Angle 6 is alternate interior angles with 4, which means it is 120.

3 0

2 years ago

NEED HELP WILLL GIVE BRAINLEST TO RIGHT ANSWER

Triss [41]

Answer:

I just got it off of brainly

5 0

2 years ago

Help me find the answer!! 2-step equation

Vladimir79 [104]

$\looparrowright \sf3\leqslant \dfrac{y}{ - 5} + 7$

$\looparrowright \sf3 - 7\leqslant \dfrac{y}{ - 5}$

$\looparrowright \sf - 4\leqslant \dfrac{y}{ - 5}$

$\looparrowright \sf - 4 \times - 5\leqslant {y}$

$\looparrowright \sf 20\leqslant {y}$

8 0

1 year ago

The curve with equation y=e^2x/4+3e^x has one stationary point.find the exact value of the coordinates of this point

Softa [21]

$y=\dfrac{e^{2x}}{4+3e^x}$
$\implies y'=\dfrac{2e^{2x}(4+3e^x)-3e^xe^{2x}}{(4+3e^x)^2}$
$\implies y'=\dfrac{8e^{2x}+3e^{3x}}{(4+3e^x)^2}$

Stationary points occur where the derivative is zero. The denominator is positive for all $x$ , so we only need to worry about the numerator.

$8e^{2x}+3e^{3x}=e^{2x}(8+3e^x)=0$

$e^{2x}>0$ for all $x$ , so we can divide through:

$8+3e^x=0\implies e^x=-\dfrac83$

But $e^x>0$ for all $x\in\mathbb R$ , so this function has no stationary points...

I suspect there may be a typo in the question.

6 0

2 years ago