1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
11

Is 3/5 and 6/12 equivalent

Mathematics
2 answers:
Furkat [3]3 years ago
8 0

No. The closest equivalent to 3/5 is 6/10 and the closest equivalent to 6/12 is 3/6.

krek1111 [17]3 years ago
7 0

Answer:

no

Step-by-step explanation:

We can simplify 6/12 by dividing the top and bottom by 6

6/12 =1/2

3/5 and 1/2

The common denominator is 10

3/5 *2/2 =6/10

1/2*5/5 = 5/10

They are not equal

You might be interested in
Which of these coordinates would represent the intercepts of the graph of the function f(x)=3x-9
4vir4ik [10]
(3,0) and (0,-9)
Explanation: type the equation in a graphing calculator and the answer is the points where the line crosses the x and y axis

7 0
2 years ago
Read 2 more answers
What is the equation of the line shown in this graph?<br><br><br><br> Enter your answer in the box
IgorLugansk [536]
This is a horizontal line at y = -3. If you want to find it mathematically, you could find the slope (y2-y1)/(x2-x1) and you would get 0 over 5, so you know the slope is zero. Pick either point and substitute the numbers into point-slope formula. I went with (3, -3) and got (y - -3) = 0(x-3). The right side is just 0, and if you subtract three from both sides to isolate y, you get the equation y = -3.
3 0
3 years ago
Read 2 more answers
Solve with interval notation Solve: 5 | x − 2 | + 4 &gt; 8
Gnesinka [82]

Answer:

x<6/5, x>14/5

Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$5\left|x-2\right|+4-4>8-4$

$\mathrm{Simplify}$

$5\left|x-2\right|>4$

$\mathrm{Divide\:both\:sides\:by\:}5$

$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$

$\mathrm{Simplify}$

$\left|x-2\right|>\frac{4}{5}$

$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$

Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

5 0
3 years ago
joe and marty are in the park playing catch. tony joins them, and the boys want to stand so that the distance between any two of
Snezhnost [94]

Answer:

not sure what the answer is

3 0
3 years ago
Nemos aquarium is filled with 2400 cm of water the base of the aquarium is 20 cm long and 12 cm wide what is the height of the w
SSSSS [86.1K]

The answer to this question is 10 cm

In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).

Then you need to divide the volume with the length and width. The equation would be:

Aquarium height= volume / length / width

Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.

7 0
2 years ago
Other questions:
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
    10·2 answers
  • Does the amount of hazardous material absorbed by the bodies of hazardous waste workers depend on gender? The level of lead in t
    9·1 answer
  • If a Naruto manga box set cost $250 total and i apply a 20% off discount code, how much will the box set be in total?
    5·2 answers
  • What is 830% written as a decimal
    9·2 answers
  • If -5x-8 =-18, is x = -2 a solution? show your work
    11·1 answer
  • Define conjecture in maths​
    15·1 answer
  • I would appreciate it if someone could help answer this problem:)
    7·1 answer
  • The output equals 1 less than three times the input
    5·1 answer
  • Simplify Please and Thank you!
    10·2 answers
  • SOMEONE PLS HELP
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!