We know that
applying the law of cosines
a² = b²+ c²<span> – 2*b*c*cos(A)
</span>
in this problem
a=?
b=20
c=9
A=90°
so
a² = b²+ c² – 2*b*c*cos(A)
but
cos (A)=0
a² = b²+ c²-----> 20²+9²----> a²=400+81----> a²=481-----> a=√481
a=21.93-----> a=22
the answer is
22
Answer:
Slope = 67 - 68 / -43 + 49
= -1 / 6
= - 1/6
Hope this helps
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Given:
40 people
box plot data:
minimum age : 20
Q1: 28
Median: 34
Q3: 42
maximum age: 48
Q1 represents 25% of the data set.
40 x 25% = 10
There are 10 people who are aged 28 and below.
1st quartile is equal to 25% of the data set, the median is equal to 50% of the data set, 3rd quartile is equal to 75% of the data set.
