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lys-0071 [83]
3 years ago
5

at the sewing store, ava bought a bag of buttons. 21 in all. 21 of the buttons were large. what percentage of the buttons wre la

rge
Physics
2 answers:
erma4kov [3.2K]3 years ago
6 0
If she only has 21 buttons and all 21 of them are large, then all of her buttons are large. so 100% of the buttons would be large.
lukranit [14]3 years ago
4 0

Answer: 100%

Explanation:

Given : The total number of buttons in the bag= 21

The number of larger buttons = 21

Then , the percentage of the buttons were large is given by :-

\dfrac{\text{Number of large buttons}}{\text{Total buttons}}\times100\\\\\dfrac{21}{21}\times100=100\%

Therefore, the percentage of the buttons were large = 100%

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The next possible wavelength is 3 y / 4 -    node - antinode - node -antinode

y / 4 = 3 m     y = 12 meters    the longest wavelength

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A)If your torsion balance deflects to an angle of 10° when your two spheres are 40cm apart, what angle will it deflect to when t
svp [43]

Answer:

Explanation:

Given

for \theta=10^{\circ}

Sphere are d=40\ cm

when sphere d_2=10\ cm apart suppose deflection is \theta _2

We know

F=k_t\cdot \theta

Where F=force between charged particle

\theta =Deflection

F=\frac{kQ_1Q_2}{r^2}=k_t\cdot \theta

\theta =\frac{k}{k_t}\times \frac{Q_1Q_2}{r^2}----1

thus \theta \propto \frac{1}{r^2}

for \theta _2

\frac{\theta _1}{\theta _2}=(\frac{r_2}{r_1})^2

\theta _2=16\times \theta _1

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(b)for 10^{\circ} deflection Potential v_1=8\ kV

Electric Potential is V=\frac{kQ}{r}

Q=\frac{V\cdot r}{k}

where V=voltage

k=constant

r=distance between charges

Put value of Q in equation 1

\theta =\frac{k}{k_t}\times \frac{V^2r^2}{k^2}

\theta =\frac{V^2r^2}{k\cdot k_t}

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therefore

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2 years ago
At the Sun Dagger in New Mexico, a dagger-shaped beam of sunlight pierces a spiral
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D

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