Why is fluorine special in terms of electronegativity?

A current of 8 A flows through a conductor. The number of electrons passing through the conductor in each second will be

diamong [38]

Answer:

8=3×1019 electrons per second.

Explanation:

4 0

3 years ago

Read 2 more answers

B. The role of the moon is greater than that of the sun in the occurrence of tides. ???

ahrayia [7]

Our sun is 27 million times larger than our moon. Based on its mass, the sun's gravitational attraction to the Earth is more than 177 times greater than that of the moon to the Earth. If tidal forces were based solely on comparative masses, the sun should have a tide-generating force that is 27 million times greater than that of the moon. However, the sun is 390 times further from the Earth than is the moon. Thus, its tide-generating force is reduced by 3903, or about 59 million times less than the moon. Because of these conditions, the sun’s tide-generating force is about half that of the moon.

7 0

3 years ago

Steel is very stiff, and the Young's modulus for steel is unusually large, 2.0×1011 N/m2. A cube of steel 25 cm on a side suppor

TEA [102]

Answer:

Force (normal) = 833.85 N Compression = 1.67 x 10⁻⁸ m

Explanation:

Given data Young's Modulus (Y) = 2 x 10¹¹ N/m², Length of one side of cube = 25 cm = 0.25 m, mass of load = 85 kg

Normal force is the force exerted upon an object that is in contact with another stable object. This force would be applied by the surface onto the object in the same vector and is used to keep the object stable while it rests on a surface.

We know from Newton's Second Law that

F = ma where m is the mass and a is the acceleration (<em>in this case due to gravity</em>) hence, the normal opposing force to the load applied by the surface would be equal to the force applied on the surface by the weight of the load on the surface, So

F (normal) = M (load) x a = 85 x 9.81 = 833.85 N

Compression is the change in length of an object by the exertion of force upon it. Using the Young's Modulus formula we can find this change in the cube of steel. The Young's Modulus is given by

Y = (F/A)/(ΔL/L), where Y is the Young's Modulus, F is the Force being applied on the object, A is the cross sectional area on which the said force is applied, ΔL is the change in length due to said force being applied and L is the original Length of the side of the cross sectional area.

Solving this for ΔL, we can re- arrange the equation

ΔL = (F x L)/(Y x A) since area of square is L x L we can simplify the equation to get

ΔL = (F)/(Y x L), substitute the values

ΔL = (833.85)/(2 x 10¹¹ x 0.25) = 1.67 x 10⁻⁸m

6 0

3 years ago

Is it possible to create a visual model (stop motion) of a wave motion using the differential equation for simple harmonic oscil

Alexeev081 [22]

Answer:

Yes.

Explanation:

A particular solution for the 1D wave equation has the form

$\Psi(x,t) \ = \ A \ sin ( \ k x \ + \omega t \ + \phi \ )$

where A its the amplitude, k the wavenumber, ω the angular frequency and φ the phase angle.

Now, for any given position $x_0$ , we can use:

$\phi_0 \ = \ \phi \ + \ k x_0$

so, the equation its:

$\Psi(x_0,t) \ = \ A \ sin ( \omega t \ + \ \phi_0 )$ .

This is the equation for a simple harmonic oscillation!

So, for any given point, we can use a simple harmonic oscillation as visual model. Now, when we move a $\delta$ distance from the original position, we got:

$x_1 = x_0 + \delta$

and

$\phi_1 = \phi \ + k x_1$

now, this its

$\phi_1 = \phi \ + k ( x_0 + \delta)$

$\phi_1 = \phi \ + k x_0 + k \delta$

$\phi_1 = \phi_0 + k \delta$

So, there its a phase angle difference of $k \delta$ . We can model this simply by starting the simple harmonic oscillation with a different phase angle.

8 0

3 years ago

Why does changing the shape on an object have no affect on the density of that object?

Anna11 [10]

It is because change in the Mass of the object balances the change in the Volume of the object equally...........

8 0

3 years ago