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pickupchik [31]
3 years ago
5

(4 points) A mother with mass m1 is skating at velocity v1 behind her daughter whose mass is m2, who is skating at v2 . Instead

of passing her, Mother inadvertently crashes into Daughter and grabs Daughter around the waist. They maintain their balance and skate off together with velocity vf , right after the collision. a) Sketch the problem with before-and-after diagrams. (You can represent the skaters as blocks). b) Is the collision best described as elastic, inelastic, or perfectly inelastic, why? c) Write the general equations for conservation of momentum in terms of m1 , m2 , v1, v2 , and final velocity vf . d) Given: m1 = 70.0 kg, v1 = 8.00 m/s m2 = 50 kg, v2= 4.00 m/s Solve for the final velocity vf . e) If the collision last 0.25 s, what is the average force delivered during the collision?

Physics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

B) collision is inelastic because they stick together after collision and share a common final velocity Vf

C) M1V1 + M2V2 = (M1 + M2)Vf

D) Vf = 6.33m/s

E) force = 3040N

Explanation:

Detailed explanation and calculation is shown in the image below

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Points A, B, and C are at the corners of an equilateral triangle of side 8 m. Equal positive charges of 4 mu or micro CC are at
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Answer:

a) 8.99*10³ V  b) 4.5*10⁻² J c) 0 d) 0

Explanation:

a)

  • The electrostatic potential V, is the work done per unit charge, by the electrostatic force, producing a displacement d from infinity (assumed to be the reference zero level).
  • For a point charge, it can be expressed as follows:

        V =\frac{k*q}{d}

  • As the electrostatic force is linear with the charge (it is raised to first power), we can apply superposition principle.
  • This means that the total potential at a given point, is just the sum of the individual potentials due to the different charges, as if the others were not there.
  • In our case, due to symmetry, the potential, at any corner of the triangle, is just the double of the potential due to the charge located at  any other corner, as follows:

        V = \frac{2*q*k}{d} = \frac{2*8.99e9N*m2/C2*4e-6C}{8m} =\\ \\ V= 8.99e3 V

  • The potential at point C is 8.99*10³ V

b)

  • The work required to bring a positive charge of 5μC from infinity to the point C, is just the product of the potential at this point times the charge, as follows:

        W = V * q = 8.99e3 V* 5e-6C = 4.5e-2 J

  • The work needed is 0.045 J.

c)

  • If we replace one of the charges creating the potential at the point  C, by one of the same magnitude, but opposite sign, we will have the following equation:

       V = \frac{8.99e9N*m2/C2*(4e-6C)}{8m}  + (\frac{8.99e9N*m2/C2*(-4e-6C)}{8m}) = 0

  • This means that the potential due to both charges is 0, at point C.

d)

  • If the potential at point C is 0, assuming that at infinity V=0 also, we conclude that there is no work required to bring the charge of 5μC from infinity to the point C, as no potential difference exists between both points.
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3 years ago
Which material is a composite? A. gold B.silicon C.polycarbonate D.aluminum
sweet [91]

Answer:

I think gold

Explanation:

6 0
3 years ago
Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through polystyrene. The waveleng
klemol [59]

Answer:

Speed:

2.01x10^{8}m/s

Wavelength:

4.24x10^{-7}m

Frequency:

4.74x10^{14}Hz

Explanation:

The speed of the laser as it travels through polystyrene can be determine by means of the equation of the refraction index:

n = \frac{c}{v} (1)

Where c is the speed of light and v is the speed of the laser in the medium.

Therefore, v will be isolated from equation 1

v = \frac{c}{n}

v = \frac{3x10^{8}m/s}{1.490}

v = 2.01x10^{8}m/s

Hence, the speed of the laser has a value of 2.01x10^{8}m/s

Frenquency:

Since, wavelength is the only one who depends on the media. Therefore the frequency in both medium will be the same.  

To determine the frequency it can be used the following equation

c = \nu \cdot \lambda  (2)

Where c is the speed of light, \nu is the frequency and \lambda is the wavelength

Then, \nu wil be isolated from equation 2.

\nu = \frac{c}{\lambda}  (3)

Before using equation 3 it is necessary to express \lamba in units of meters.

\lambda = 632.8nm . \frac{1m}{1x10^{9}nm} ⇒ 6.328x10^{-7}m

\nu = \frac{3x10^{8}m/s}{6.328x10^{-7}m}

\nu = 4.74x10^{14}s^{-1}

\nu = 4.74x10^{14}Hz

Hence, the frequency of the laser has a value of 4.74x10^{14}Hz

Wavelength:

To determine the wavelength it can be used:

v = \nu \cdot \lambda

\lambda = \frac{v}{\nu}

Where v is the speed of the laser through the polystyrene.

\lambda = \frac{2.01x10^{8}m/s}{4.74x10^{14}s^{-1}}

\lambda = 4.24x10^{-7}m

Hence, the wavelength of the laser has a value of 4.24x10^{-7}m

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To find the work done on the particle, the following is the solution:

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W = -5e^(-x/5 + 5) from 0 to 1

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The work done is 135 J.

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1. Explain a stretching routine for your work environment. As you consider your routine, keep in mind the specific individuals w
weeeeeb [17]

Answer:

Explanation:

A stretching routine should target most of the main muscles in the body and at least one stretching exercise per section of the body. Also in a work environment since individual's sizes, ages, and cultures vary you should design a routine that is for beginners and very easy and effective. Regardless, each individual should be able to move at their own pace and push as far as they are physically able. One such routine would be the one in the attached picture below which targets all major areas, is easy and effective. It starts at the neck muscles and works its way down the arms, back, and legs.

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