The mass of the water is 1580 g.
<h3>What is the amount of water formed?</h3>
We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from 7.9 x 10-3 atm to 1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.
Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm
Using;
PV = nRT
n = PV/RT
n = 7.78 * 10^-3 atm * 2.4 x10^5 l/0.082 * (39 + 273)
n = 85 moles
Since 1 mole of carbon dioxide produces 1 mole of water
85 moles of carbon dioxide produces 85 mole of water
Mass of water produced = 85 mole * 18 g/mol
= 1580 g
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Increases with
hope this helped :))
correct me if i’m wrong
A compound that binds to a receptor but does not activate the neuron is known as an Antagonist.
A receptor is a large protein molecule on a neuron that gets activated when a ligand binds to it such as a drug or hormone, or when electrical impulses pass through it.
An antagonist is a drug or hormone that binds to receptor, but instead of activating the receptor, it blocks or dampens the activation of the neuron. Antagonist drugs are used to interfere with the normal function or operation of a protein receptor.
Depending on the nature of the antagonist or the receptor it's bound to, the effects of antagonists may be permanent or temporary.
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The answer is Fe3O2 because there’s 2 oxygen and 3 iron
Answer:
a) 1.61 mol
b) Al is limiting reactant
c) HBr is in excess
Explanation:
Given data:
Moles of Al = 3.22 mol
Moles of HBr = 4.96 mol
Moles of H₂ formed = ?
What is limiting reactant =
What is excess reactant = ?
Solution:
Chemical equation:
2Al + 2HBr → 2AlBr + H₂
Now we will compare the moles:
Al : H₂
2 : 1
3.22 : 1/2×3.22 = 1.61 mol
HBr : H₂
2 : 1
4.96 : 1/2×4.96 = 2.48 mol
The number of moles of H₂ produced by Al are less it will be limiting reactant while HBr is present in excess.
Moles of H₂ :
Number of moles of H₂ = 1.61 mol