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olga55 [171]
3 years ago
12

Consider an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen c

oncentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire. (a) Which electrode will corrode? (b) Write half-cell reactions for the anodic reaction and the cathodic reaction.
Chemistry
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

Explanation:

In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.

(a) Which electrode will corrode?

The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.

Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

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What is the mass of the object?
galben [10]

Answer:

37.3

263.5

Explanation:

The scale measures hundreds of units, tens of units, units, and parts of units (1 decimal place.

Scale 1

Hundreds 0 * 100 = 0

Tens: 3 * 10 = 30

Units: 7 * 1 = 7

1/10 unit = 3* 0.1 = 0.3

Total 30 + 7 + 0.3 = 37.3

Scale 2

Hundreds 2 * 100 = 200

Tens: 6 * 10 = 60

Units: 3 * 1 = 3

1/10 unit = 5* 0.1 = 0.5

Total = 200 + 60 + 3 + 0.5 = 263.5

7 0
3 years ago
a. Calculate the pH of a solution that has [H3O+]= 4.3 x 10-5 M. b. Is the solution acidic or basic? How do you know?
Luda [366]

Answer:

* pH=4.37

* The solution is acidic since the pH is below 7.

Explanation:

Hello,

In this case, we can mathematically define the pH by:

pH=-log([H_3O^+])

Thus, for the given hydronium concentration we simply compute the pH:

pH=-log(4.3x10^{-5})=4.37

Thereby, we conclude the solution is acidic due to the fact that the pH is below 7 which is the neutral point and above it the solutions are basic.

Regards.

3 0
2 years ago
If 45.0 mL of ethanol (density = 0.789 g/mL) initially at 8.0 ∘C is mixed with 45.0 mL of water (density = 1.0 g/mL) initially a
strojnjashka [21]

Answer : The final temperature of the mixture is, 22.14^oC

Explanation :

First we have to calculate the mass of ethanol and water.

\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 45.0mL=35.5g

and,

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ethanol = 2.42J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol = 35.5 g

m_2 = mass of water = 45.0 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 8.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get:

35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.14^oC

Therefore, the final temperature of the mixture is, 22.14^oC

3 0
3 years ago
About how much is one liter?
AleksAgata [21]
Look at the liter man it’s a great way to learn how much every liquid measurement is
7 0
3 years ago
PLEASE ANSWER I WILL MAKE BRAINLIEST!!!
tangare [24]
Using an example like Christmas lights, I would say yes because normally a lot of them would go out if one light is broken.
3 0
2 years ago
Read 2 more answers
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