Answer:
56.17% is percent composition of Sb in the molecule
Explanation:
Percent composition is the percent in mass of each element present in a particular molecule.
In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:
<em>Mass Sb:</em>
1mol * (121.76g/mol) = 121.76g
<em>Mass F:</em>
1 mol SbF₅ = 5 moles F * (19g / mol) = 95g
<em>Total mass:</em>
121.76g + 95g = 216.76g
And percent composition of Sb:
121.76g / 216.76g * 100 =
<h3>56.17% is percent composition of Sb in the molecule</h3>
Answer:
6.97 atm was the equilibrium pressure of HBr .
Explanation:
The value of the equilibrium constant =

Initially:
0 0 7.10 atm
At equilibrium
x x (7.10-2x)
The expression of equilibrium constant can be written as:


Solving for x:
x = 0.065
Partial pressure of HBr at equilibrium :(7.10 - 2 × 0.065) atm = 6.97 atm
6.97 atm was the equilibrium pressure of HBr .
Answer:
n=17.85 moles
Explanation:
Given mass is, m = 1.5 kg = 1500 g
The molar mass of sodium bicarbonate is, M = 84.007 g/mol
We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.

<h2>
So, there are 17.85 moles in 1.5 kg of Sodium bicarbonate.</h2>
D. The nucleus is the control center of the cell
Answer:
Explanation:
(12 x 104 ) x (5 x 10-²) = 6 x 10 ³ 6 x 105 6.0x10²
1. (12 x 104 ) = 1248 or 1.248 x 10^3
2. (1.248 x 10^3)(5 x 10^-2) = 6.240 x 10^1 or 60 rounded to 1 sig fig
I don't understand "= 6 x 10 ³ 6 x 105 6.0x10² "